一.题目: 题目来源WUSTOJ 二.源代码: #include<stdio.h> int main() { int n, m, num, sum, i, j, k; while (scanf("%d%d", &n, &m) != EOF) { k = 2; // 表示偶数序列 num = n / m + (n % m ? 1 : 0); // 平均值的个数,n%m不为0则num加1 for (i = 0; i < num; i++) { sum =…
1163: 零起点学算法70--Yes,I can! Time Limit: 1 Sec Memory Limit: 64 MB 64bit IO Format: %lldSubmitted: 938 Accepted: 714[Submit][Status][Web Board] Description Boys and girls: Good evening. Welcome to take the select contest. I wish you can be an ACMer…