题目链接:https://vjudge.net/problem/UVA-796 In a computer network a link L, which interconnects two servers, is considered critical if there are at least two servers A and B such that all network interconnection paths between A and B pass through L. Remo…

本题大意:求出一个无向图的桥的个数并且按照顺序输出所有桥. 本题思路:注意判重就行了,就是一个桥的裸题. 判重思路目前知道的有两种,第一种是哈希判重,第二种和邻接矩阵的优化一样,就是只存图的上半角或者下半角. 参考代码: /************************************************************************* > File Name: uva-796.critical_links.cpp > Author: CruelKing >…

题目链接:https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=737 求桥的数量,也就是割边的数量.输入有点小坑,左右括号外必须得有个空格才行,起初以为是转义的问题. /* ━━━━━┒ギリギリ♂ eye! ┓┏┓┏┓┃キリキリ♂ mind! ┛┗┛┗┛┃＼○/ ┓┏┓┏┓┃ / ┛┗┛┗┛┃ノ) ┓┏┓┏┓┃ ┛┗┛┗┛┃ ┓┏┓┏┓┃ ┛┗…

用tarjan缩点 然后用dfn[u] < low[v]缩点并且保存起来 在sort一遍输出 #include<stdio.h> #include<string.h> #include<algorithm> using namespace std; ; struct Node { int u; int v; int next; }; struct Edge{ int u; int v; }; Edge edge[maxn]; Node node[maxn * ];…

题意:求桥 思路:求桥的条件是:(u,v)是父子边时 low[v]>dfn[u] 所以我们要解决的问题是怎么判断u,v是父子边(也叫树枝边).我们在进行dfs的时候,要加入一个fa表示当前进行搜索的点的父节点.v=edge[v].v,如果dfn[v]==0即没访问过,那么肯定是父子边:如果v已经被访问过,我们就要做出筛选,只有v!=fa才进行low[u]=min(low[u],dfn[v]),因为v==fa时,(u,v)变成了返祖边,这时候low[u]被刷新成为fa的dfn,但是low是通过父子…

In a computer network a link L, which interconnects two servers, is considered critical if there are atleast two servers A and B such that all network interconnection paths between A and B pass through L.Removing a critical link generates two disjoin…

Critical Links 题目链接:https://vjudge.net/problem/UVA-796 Description: In a computer network a link L, which interconnects two servers, is considered critical if there are at least two servers A and B such that all network interconnection paths between…

题目链接:https://vjudge.net/problem/UVA-796 题目:裸的求桥,按第一个元素升序输出即可. #include <iostream> #include <cstdio> #include <algorithm> #include <vector> using namespace std; #define pb push_back #define fi first #define se second ; int n,tot,tim…

题目大意:双向联通图, 现在求减少任意一边使图的联通性改变,按照起点从小到大列出所有这样的边 解题思路:双向边模版题 tarjan算法 代码如下: #include<bits/stdc++.h> using namespace std; ; vector<int>vec[N]; pair<int, int>edge[N]; int dfn[N], low[N]; int res, ans; void tarjan(int u, int f) { dfn[u] = low…

题目是PDF就没截图了 这题似乎没有重边,若有重边的话这两点任意一条边都不是桥,跟求割点类似的原理 代码: #include <stdio.h> #include <bits/stdc++.h> using namespace std; #define INF 0x3f3f3f3f #define CLR(arr,val) memset(arr,val,sizeof(arr)) #define LC(x) (x<<1) #define RC(x) ((x<<…