【Leetcode 21. Merge Two Sorted Lists（easy）】的更多相关文章

Leetcode 21. Merge Two Sorted Lists（easy）

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 递归实现: /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(i…

【leetcode】Merge Two Sorted Lists（easy）

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 思路:使用伪头部 class Solution { public: ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) { ListNode fakehead();…

LeetCode：21. Merge Two Sorted Lists（Easy）

1. 原题链接 https://leetcode.com/problems/merge-two-sorted-lists/description/ 2. 题目要求 给出两个已经从小到大排序的链表ls1.ls2,进行合并,合并后仍有序,返回合并后的链表 3. 解题思路 创建一个表头指针headPointer和一个定位指针locatePointer,headPointer用来保存头结点. 同时对ls1和ls2进行遍历,当ls1的值小于ls2的值时,locatePointer指向ls1,否则指向ls2…

LeetCode 21. Merge Two Sorted Lists （合并两个有序链表）

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题目标签:Linked List 题目给了我们两个lists,让我们有序的合并两个 lists. 这题利用递归可以从list 的最后开始向前链接nodes,代码很简洁,清楚. Java Solution: Runti…

# 蜗牛慢慢爬 LeetCode 21. Merge Two Sorted Lists [Difficulty: Easy]

题目 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 翻译 合并两个有序的链表 Hints Related Topics: LinkedList 参考 归并排序-维基百科,可以递归也可以迭代,基本的链表操作 代码 Java /** * Definition for…

21.Merge Two Sorted Lists（链表）

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(in…

LeetCode 21 Merge Two Sorted Lists （有序两个链表整合）

题目链接 https://leetcode.com/problems/merge-two-sorted-lists/?tab=Description   Problem: 已知两个有序链表(链表中的数值递增排列).将这两个链表进行合并操作,并且满足递增排列 即合并后仍为有序链表.     递归进行合并操作.mergeTwoList(ListNode list1, ListNode list2)      当list1==null时 return list2;      当list2==null时…

LeetCode 21. Merge Two Sorted Lists（c++)

要定义两个链表 判断时依次对应每一个链表的值进行判断即可. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { L…

LeetCode 21. Merge Two Sorted Lists（合并两个有序链表）

题意:合并两个有序链表 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { if(l1 == NULL) retu…

21. Merge Two Sorted Lists【easy】

21. Merge Two Sorted Lists[easy] Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 解法一: /** * Definition for singly-linked list. * struct ListNode { * int val…