Leetcode 25. Reverse Nodes in k-Group 以每组k个结点进行链表反转(链表) 题目描述 已知一个链表,每次对k个节点进行反转,最后返回反转后的链表 测试样例 Input: k = 2, 1->2->3->4->5 Output: 2->1->4->3->5 Input: k = 3, 1->2->3->4->5 Output: 3->2->1->4->5 详细分析 按照题目要求…
Reverse Nodes in k-Group Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the valu…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only nod…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out nodes in…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only nod…
[抄题]: 给你一个链表以及一个k,将这个链表从头指针开始每k个翻转一下.链表元素个数不是k的倍数,最后剩余的不用翻转. [思维问题]: [一句话思路]: // reverse head->n1->..->nk->next.. // to head->nk->..->n1->next.. // return n1 每k个转一次,再递归 [输入量]:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): [画图]: [一刷]: h…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only nod…
题意:给一个单链表,每k个节点就将这k个节点反置,若节点数不是k的倍数,则后面不够k个的这一小段链表不必反置. 思路:递归法.每次递归就将k个节点反置,将k个之后的链表头递归下去解决.利用原来的函数接口即可,不用重新定义. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; *…
Write a function that takes a string as input and reverse only the vowels of a string. Example 1:Given s = "hello", return "holle". Example 2:Given s = "leetcode", return "leotcede". 这道题让我们翻转字符串中的元音字母,元音字母有五个a,e,i,o…
Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". Update (2015-02-12): For C programmers: Try to solve it in-place in O(1) space. click to show clarification. Cl…
# Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def reverseKGroup(self, head, k): """ :type head: ListNode :type k: int :rtype: ListNode "…
题意:将指定的一段位置[m,n]的链表反置,返回链表头. 思路:主要麻烦在链表头,如果要从链表头就开始,比较特殊. 目前用DFS实现,先找到m-1的位置,再找到n+1的位置,中间这段就是否要反置的,交给DFS解决,用个计数器来统计已经反置的个数即可. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(N…
题意: 将单恋表反转. 思路: 两种方法:迭代和递归. 递归 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* give_me_your_son( ListNode* far, ListNode* s…
1. 题目 2. 解答 首先,利用快慢指针确定链表的总结点数. 偶数个结点时,结点个数等于 i * 2. 奇数个结点时,结点个数等于 i * 2 + 1. 然后将链表的每 K 个结点划分为一组.循环对每组的子链表进行翻转,并依次拼接起来. 最后,将多余的结点拼接在新链表最后面即可. 代码如下 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(in…
题目: Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out nodes in…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out nodes in…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only nod…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out nodes in…
题目 Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out nodes…
题目描述: 中文: 给你一个链表,每 k 个节点一组进行翻转,请你返回翻转后的链表. k 是一个正整数,它的值小于或等于链表的长度. 如果节点总数不是 k 的整数倍,那么请将最后剩余的节点保持原有顺序. 示例 : 给定这个链表:1->2->3->4->5 当 k = 2 时,应当返回: 2->1->4->3->5 当 k = 3 时,应当返回: 3->2->1->4->5 说明 : 你的算法只能使用常数的额外空间. 你不能只是单纯的改…
题目: Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only…
给出一个链表,一次翻转 k 个指针节点,并返回修改后的链表.k 是一个正整数,并且小于等于链表的长度.如果指针节点的数量不是 k 的整数倍,那么最后剩余的节点应当保持原来的样子.你不应该改变节点的值,只有节点位置本身可能会改变.题目应当保证,仅使用恒定的内存.例如,给定这个链表:1->2->3->4->5当 k = 2时,应当返回: 2->1->4->3->5当 k = 3时,应当返回: 3->2->1->4->5详见:https:/…
题目:Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only…
题目链接 题目要求: Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the node…
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out nodes in…
hard! 题目描述: 给出一个链表,每 k 个节点为一组进行翻转,并返回翻转后的链表. k 是一个正整数,它的值小于或等于链表的长度.如果节点总数不是 k 的整数倍,那么将最后剩余节点保持原有顺序. 示例 : 给定这个链表:1->2->3->4->5 当 k = 2 时,应当返回: 2->1->4->3->5 当 k = 3 时,应当返回: 3->2->1->4->5 说明 : 你的算法只能使用常数的额外空间. 你不能只是单纯的改变…
https://leetcode-cn.com/problems/reverse-nodes-in-k-group/solution/javadi-gui-fang-fa-100-by-chadriy-imdgvs6udp/ https://leetcode-cn.com/problems/reverse-nodes-in-k-group/solution/tu-jie-kge-yi-zu-fan-zhuan-lian-biao-by-user7208t/ 描述 给你一个链表,每 k 个节点一组…
25. K 个一组翻转链表 给你一个链表,每 k 个节点一组进行翻转,请你返回翻转后的链表. k 是一个正整数,它的值小于或等于链表的长度. 如果节点总数不是 k 的整数倍,那么请将最后剩余的节点保持原有顺序. 示例 : 给定这个链表:1->2->3->4->5 当 k = 2 时,应当返回: 2->1->4->3->5 当 k = 3 时,应当返回: 3->2->1->4->5 说明 : 你的算法只能使用常数的额外空间. 你不能只是…
给出一个链表,每 k 个节点一组进行翻转,并返回翻转后的链表. k 是一个正整数,它的值小于或等于链表的长度.如果节点总数不是 k 的整数倍,那么将最后剩余节点保持原有顺序. 示例 : 给定这个链表:1->2->3->4->5 当 k = 2 时,应当返回: 2->1->4->3->5 当 k = 3 时,应当返回: 3->2->1->4->5 说明 : 你的算法只能使用常数的额外空间. 你不能只是单纯的改变节点内部的值,而是需要实际…