了不起的分支和循环01 让编程改变世界 Change the world by program 我们今天的主题是"了不起的分支和循环",为什么小甲鱼不说C语言,不说Python了不起,却毫不吝啬地对分支和循环这两个知识点那么葱白呢? 大家之前几节课也接触了最简单的分支和循环的使用,那么小甲鱼希望大家思考一下:如果没有分支和循环,我们的程序会变成怎样? 没错,就会变成一堆从上到下依次执行.毫无趣味的垃圾代码!还能实现算法吗?扯淡,没有了循环,连打印100次老婆我爱你,都需要在键盘上敲10…
问题: 设计一函数,求整数区间[a,b]和[c,d]的交集.(c/c++.Java.Javascript.C#.Python) 1.Python: def calcMixed(a,b,c,d): rtn=[] list1=range(a,b+1) for num in range(c,d+1): if num in list1: rtn.append(num) return rtn mixed=calcMixed(1,8,5,9) print(mixed) 2. …
POJ1811 给一个大数,判断是否是素数,如果不是素数,打印出它的最小质因数 随机素数测试(Miller_Rabin算法) 求整数素因子(Pollard_rho算法) 科技题 #include<cstdlib> #include<cstdio> ; ; int tot; long long n; long long factor[maxn]; long long muti_mod(long long a,long long b,long long c) { //(a*b) mod…
求整数最大的连续0的个数 A binary gap within a positive integer N is any maximal sequence of consecutive zeros that is surrounded by ones at both ends in the binary representation of N. For example, number 9 has binary representation 1001 and contains a binary g…
Count the Colors Time Limit: 2 Seconds Memory Limit: 65536 KB Painting some colored segments on a line, some previously painted segments may be covered by some the subsequent ones. Your task is counting the segments of different colors you can s…
In order to encourage Hiqivenfin to study math, his mother gave him a sweet candy when the day of the month was a prime number. Hiqivenfin was happy with that. But several days later, his mother modified the rule so that he could get a candy only whe…
用HTML和JSp来实现 1.HTML调用JSp语法:<script type="text/javascript" src="整数和jsp.js"></script> 2.在HTML中建一个文本框来输入数字,定义一个id 3.在JSP中定义一个变量来接收这个id,并通过方法来进行运行判断,用alert来输出结果 function add() { var a = document.getElementById("aaa&…
如果有题目要求整数A和B二进制表示中多少位是不同的? 那我们要先考虑一个unsigned类型中变量1的个数?我们可以考虑简单的移位运算,向右移位,我们进行判断如果不是1直接丢掉,使用&运算符即可. int count(unsigned A) { int num = 0; while(A){ num += A & 0x01; A >>= 1; } return num } 由此,比较两个整数二进制表示中有多少不同,先将两数进行异或运算A^B,相同的位就变成0了,然后用上述方法统计…
while循环结构: #while 条件: print("any") print("any") 死循环案例 num = 1 while num<=10 : print(num) 在CMD中按CTRL+C可以中断 输出1-10的数字 num = 1 while num<=10 : print(num) num+=1 输出1-100之间所有的偶数 num = 2 while num<=100 : print(num) num+=2 方法二: num =…