HDU1372 Knight Moves（BFS） 2016-07-24 14:50 69人阅读评论(0) 收藏

【HDU1372 Knight Moves（BFS） 2016-07-24 14:50 69人阅读评论(0) 收藏】的更多相关文章

HDU1372 Knight Moves（BFS） 2016-07-24 14:50 69人阅读评论(0) 收藏

Knight Moves Problem Description A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves that visits each square of a given set of n squares on a chessboard exactly once.…

THE DRUNK JAILER 分类： POJ 2015-06-10 14:50 13人阅读评论(0) 收藏

THE DRUNK JAILER Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 24918 Accepted: 15632 Description A certain prison contains a long hall of n cells, each right next to each other. Each cell has a prisoner in it, and each cell is locked…

iOS 发布流程分类： ios相关 app相关 2015-05-22 14:50 186人阅读评论(0) 收藏

1.登陆苹果开发者中心http://developer.apple.com(99美元账号) 2.进入itunes connect 3.选择Manage Your Apps 4.选择Add New App 5.填写项目相关信息,不知道怎么填的点击问号查看,Bundle ID Suffix需要与上一篇申请发布证书中锁填的后缀一致,否则在上传项目时会出错,需要重新打包 6.然后是选择项目价格和日期 7.接下来的页面要填写项目的完整信息页面比较大,四张截图 ① ② 这个一般全部选择None ③ URL…

js中二维数组的创建方法 2017-04-04 14:50 120人阅读评论(0) 收藏

法一:var myarr=[[0,1,2],[1,2,3]]; 将[0,1,2]看做原来的0,将[1,2,3]看做原来的1,而二者又分别为子数组如myarr[0][1]=1,myarr[1][1]=3 法二: var myarr=new Array(); //先声明一维 for(var i=0;i<2;i++){ //一维长度为2 myarr[i]=new Array(); //再声明二维 for(var j=0;j<3;j++){ //二维长度为3 myarr[i][j]=i+j; //…

A Knight's Journey 分类： dfs 2015-05-03 14:51 23人阅读评论(0) 收藏

A Knight’s Journey Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 34085 Accepted: 11621 Description Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around…

HDU1072 Nightmare（BFS） 2016-07-24 14:02 40人阅读评论(0) 收藏

Nightmare Problem Description Ignatius had a nightmare last night. He found himself in a labyrinth with a time bomb on him. The labyrinth has an exit, Ignatius should get out of the labyrinth before the bomb explodes. The initial exploding time of th…