这是使用DFS来解数组类题的典型题目,像求子集,和为sum的k个数也是一个类型 解题步骤: 1:有哪些起点,例如,数组中的每个元素都有可能作为起点,那么用个for循环就可以了. 2:是否允许重复组合 3:处理某个数,判断结果 4:dfs递归 5:还原现场 一:Permutations Given a collection of numbers, return all possible permutations. For example,[1,2,3] have the following per…

# import itertools # # my_list = [1, 2, 3, 4, 5, 6] # # combinations = itertools.combinations(my_list, 3) # permutations = itertools.permutations(my_list, 3) import itertools word = 'sample' my_letters = 'plmeas' combinations = itertools.combinations…

Write a program to solve a Sudoku puzzle by filling the empty cells. Empty cells are indicated by the character '.'. You may assume that there will be only one unique solution. A sudoku puzzle... ...and its solution numbers marked in red. 这道求解数独的题是在之…

# test permutations and combinations import itertools as it for i in it.combinations('abcd',2): print (i) for j in it.combinations('123456',4): print (j) for k in it.permutations('ABCDEF',2): print (k) for m in it.product('ZXY','1234'): print (m) lis…

为什么要挑战自己在代码里不写for loop?因为这样可以迫使你去使用比较高级.地道的语法或库.文中以python为例子,讲了不少大家其实在别人的代码里都见过.但自己很少用的语法. 这是一个挑战.我要你避免在任何情况下写for循环.同样的,我也要你找到一种场景——除了用for循环以外,用其他方法写都太难.请分享你的发现,我非常想听到这些 距离我开始探索超棒的Python语言特性已经有一段时间了.一开始,这只是我给自己的一个挑战,练习使用更多的语言特性来替代我从其他编程语言那里所学到的.但是事情渐…

  """ product 笛卡尔积 permutations 排列 combinations 组合,没有重复 combinations_with_replacement 组合,有重复 用itertools.都一个立马搞定,无需多层循环 """ # 以下完成0,1,2,3,4,5,6,7,8,9排列不重复的个数 import itertools data=[] ',10): ': data.append("".join(i))…

首先,让我们退一步看看在写一个for循环背后的直觉是什么: 1.遍历一个序列提取出一些信息 2.从当前的序列中生成另外的序列 3.写for循环已经是我的第二天性了,因为我是一个程序员 幸运的是,Python里面已经有很棒的工具帮你达到这些目标!你需要做的只是转变思想,用不同的角度看问题. 不到处写for循环你将会获得什么 1.更少的代码行数 2.更好的代码阅读性 3.只将缩进用于管理代码文本 Let’s see the code skeleton below: 看看下面这段代码的构架: Pyth…

itertools functions accumulate() compress() groupby() starmap() chain() count() islice() takewhile() chain.from_iterable() cycle() permutations() tee() combinations() dropwhile() product() zip_longest() combinations_with_replacement() filterfalse() r…

Write a program to solve a Sudoku puzzle by filling the empty cells. A sudoku solution must satisfy all of the following rules: Each of the digits 1-9 must occur exactly once in each row. Each of the digits 1-9 must occur exactly once in each column.…

8.02  Physics II (电磁学基础) Introduction to electromagnetism and electrostatics: electric charge, Coulomb's law, electric structure of matter; conductors and dielectrics. Concepts of electrostatic field and potential, electrostatic energy. Electric curr…

Leetcode--回溯法常考算法整理 Preface Leetcode--回溯法常考算法整理 Definition Why & When to Use Backtrakcing How to Use Backtracking Leetcode Problems N-Queens Permutations II Combinations Sudoku Solver Definition First, let's see the definition of backtracking given b…

Python Coding Interview Python Advanced Use enumerate() to iterate over both indices and values Debug problematic code with breakpoint() Format strings effectively with f-strings Sort lists with custom arguments Use generators instead of list compreh…

可迭代对象就像密闭容器里的水,有货倒不出 itertools是python内置的标准模块,提供了很多简洁又高效的专用功能,使用得当能够极大的简化代码行数,同时所有方法都是实现了生成器函数,这就意味着极大的节省内存. itertools提供的功能主要分为三大块,以最新版本的3.10为例: 对可迭代对象无限迭代,无限输出 对可迭代对象有限迭代 对可迭代对象排列组合 方法如下: 导入包 >>> from iteratortools import * 无限迭代 iteratortools.cou…

结果为: 显然,combinations方法重点在组合,permutations方法重在排列. 还有就是,combinations和permutations返回的是对象地址,原因是在python3里面,返回值已经不再是list,而是iterators(迭代器), 所以想要使用,只用将iterator 转换成list 即可, 还有其他一些函数返回的也是一个对象,需要list转换,比如 list(map())等 . ---------------------  作者:mishi_zcf  来源:CS…

combinations方法重点在组合,permutations方法重在排列. combinations和permutations返回的是对象地址,原因是在python3里面,返回值已经不再是list,而是iterators(迭代器), 所以想要使用,只用将iterator 转换成list 即可…

最近编程时经常要用到排序组合的代码,想当年还抱着一些情况买了一本<组合数学>,不过现在这货也不知道被自己放哪里了,估计不会是垫桌子腿了吧. 由于去年去东北大学考博面试的时候遇到过可能涉及排列组合的编程题,要我当时很是十分的下不来台,所以现在遇到这货比较敏感,虽然用到的时候直接调用库就万事大吉,不过细细想来总觉不妥,遂把库函数的说明文档调了出来. https://docs.python.org/dev/library/itertools.html#itertools.combinations i…

Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. For example,If n = 4 and k = 2, a solution is: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ] 这道题让求1到n共n个数字里k个数的组合数的所有情况,还是要用深度优先搜索DFS来解,根据以往的经验,像这种要求出所有结果的集合,一般…

Given a collection of numbers, return all possible permutations. For example,[1,2,3] have the following permutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], and [3,2,1]. 这道题是求全排列问题,给的输入数组没有重复项,这跟之前的那道Combinations 组合项 和类似,解法基本相同,但是不同点在于那道不同的数字顺序只…

Given a digit string, return all possible letter combinations that the number could represent. A mapping of digit to letters (just like on the telephone buttons) is given below. Input:Digit string "23" Output: ["ad", "ae", &q…

在python3.6中,如下例子: keys = list(newKeywords.keys()) resultkeys = list(itertools.combinations(keys,3)) 当上面中的Keys太长时会发生MemoryError错误,解决办法: keys = list(newKeywords.keys()) resultkeys = itertools.combinations(keys,3) for rkey in resultkeys: print(rkey) 据下面…

Permutations Given a collection of numbers, return all possible permutations. For example,[1,2,3] have the following permutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], and [3,2,1]. SOLUTION 1: 经典的递归回溯题目,一次ACCEPT. 请也参考上一个题目LeetCode: Combination…

题目:求所有全排列 难度:Medium 题目内容: Given a collection of distinct integers, return all possible permutations. 翻译:给定一组各不相同的整数,返回所有可能的排列. Example: Input: [1,2,3] Output: [ [1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], [3,2,1] ] 我的思路:每种情况中,每一个元素只出现一次,只是之间的顺序不同,那么…

题目: Given a collection of distinct numbers, return all possible permutations. For example,[1,2,3] have the following permutations: [ [1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], [3,2,1] ] 题解: 之前解过Next Permutation,故这个题可以重复调用nextPermutation函数产生全排列 Solu…

Given a collection of distinct integers, return all possible permutations. Example: Input: [1,2,3] Output: [ [1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], [3,2,1] ] 这道题是求全排列问题,给的输入数组没有重复项,这跟之前的那道 Combinations 和类似,解法基本相同,但是不同点在于那道不同的数字顺序只算一种,是一道典型的组合题,…

Given a string containing digits from 2-9inclusive, return all possible letter combinations that the number could represent. A mapping of digit to letters (just like on the telephone buttons) is given below. Note that 1 does not map to any letters. E…

Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. For example,If n = 4 and k = 2, a solution is: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ] 分析: 组合的实现,之前实现过全排列,递归求解 class Solution { public: vector<vector<int…

Given a collection of numbers that might contain duplicates, return all possible unique permutations. For example,[1,1,2] have the following unique permutations: [ [1,1,2], [1,2,1], [2,1,1] ] 分析: 全组合的思想,保证start和end之间交换的时候中间没有与end相同的数字 class Solution…

Numbers can be regarded as product of its factors. For example, 8 = 2 x 2 x 2; = 2 x 4. Write a function that takes an integer n and return all possible combinations of its factors. Note: Each combination's factors must be sorted ascending, for examp…

Given a collection of numbers that might contain duplicates, return all possible unique permutations. For example,[1,1,2] have the following unique permutations:[1,1,2], [1,2,1], and [2,1,1]. 这道题是之前那道Permutations 全排列的延伸,由于输入数组有可能出现重复数字,如果按照之前的算法运算,会有…

链接:http://poj.org/problem?id=2369 Permutations Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 3039   Accepted: 1639 Description We remind that the permutation of some final set is a one-to-one mapping of the set onto itself. Less formal…