i son/pa ppid pid fpid parent parent parent child child parent child parent parent child child child parent child 上图是fork()连续三次的结果,做图如下:…

Apple Tree Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 18623   Accepted: 5629 Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka likes apple very much, so he has been…

Apple Tree Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 27092   Accepted: 8033 Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka likes apple very much, so he has been…

Apple Tree Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 26762   Accepted: 7947 Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka likes apple very much, so he has been…

                                                          Apple Tree Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 27470   Accepted: 8140 Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will gr…

今天一位朋友去一个不错的外企面试linux开发职位,面试官出了一个如下的题目: 给出如下C程序,在linux下使用gcc编译: #include "stdio.h" #include "sys/types.h" #include "unistd.h" int main() { pid_t pid1; pid_t pid2; pid1 = fork(); pid2 = fork(); printf("pid1:%d, pid2:%d\n&…

Apple Tree Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 25904   Accepted: 7682 Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka likes apple very much, so he has been…

先预览一下工程的目录树: 实现的功能:master进程启动slave进程. 看看Makefile内容: all: master.out slave.out master.out: master.cpp g++ master.cpp -o master.out slave.out: slave.cpp g++ slave.cpp -o slave.out clean: rm -rf *.out master.cpp内容: /*************************************…

Apple Tree Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 16180   Accepted: 4836 Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka likes apple very much, so he has been…

一.进程控制块PCB-stack_struct 进程在操作系统中都有一个结构,用于表示这个进程.这就是进程控制块(PCB),在Linux中具体实现是task_struct数据结构,它主要记录了以下信息: 状态信息,例如可执行状态.就绪状态.阻塞状态等. 性质,由于unix有很多变种,进行有自己独特的性质. 资源,资源的链接比如内存,还有资源的限制和权限等. 组织,例如按照家族关系建立起来的树(父进程.子进程等). task_struct结构体内容非常庞大,暂时没有去分析源代码,以后有时间再去研究…

转载http://www.cnblogs.com/leoo2sk/archive/2009/12/11/talk-about-fork-in-linux.html 给出如下C程序,在linux下使用gcc编译: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 #include "stdio.h" #include "sys/types.h" #include "unistd.h" int main() {     pid_t p…

[原文地址]http://blog.csdn.net/hikaliv/article/details/4276758 [cpp] view plaincopy   for( i = 0; i < 5; i++ ) if( fork() == 0 ) continue; 共生成多少个子进程? 简查了一下 fork() 的知识,它调用一次,返回两次,进入子进程并返回一次,然后退到父进程再返回一次,子进程中返回值为 0,父进程中返回的是子进程的进程号. 答案是 31. 如上图所示,这就是一个二项树,二…

K-th Number Time Limit: 20000MS   Memory Limit: 65536K Total Submissions: 31790   Accepted: 9838 Case Time Limit: 2000MS Description You are working for Macrohard company in data structures department. After failing your previous task about key inser…

线段树的合并..对于一个点x, 我们只需考虑是否需要交换左右儿子, 递归处理左右儿子. #include<bits/stdc++.h> using namespace std; #define M(l, r) (((l) + (r)) >> 1) typedef long long ll; ; ; struct Node *null, *pt; struct Node { Node *l, *r; int cnt; Node() : cnt() { l = r = null; }…

3110: [Zjoi2013]K大数查询 Time Limit: 20 Sec   Memory Limit: 512 MB Submit: 418   Solved: 235 [ Submit][ Status][ Discuss] Description 有N个位置,M个操作.操作有两种,每次操作如果是1 a b c的形式表示在第a个位置到第b个位置,每个位置加入一个数c 如果是2 a b c形式,表示询问从第a个位置到第b个位置,第C大的数是多少. Input 第一行N,M 接下来M行,…

出这题的人是怎么想出来的…… 言归正传,这题是二分图套值域线段树. 首先经过 @Vfleaking的神奇建图后,把图拆成二分图, 不妨利用有向图最小割的性质建图(以前我一直以为最小割和边的方向无关,可这样的话很奇怪哦……) 理解悲剧…… 我们可以利用边有向的性质解决黑白色块…… 然后发现线段树很多……主席树闪亮登场 然后·就这麽A了?………… #include<cstdio> #include<cstdlib> #include<cstring> #include<…

1367: [Baltic2004]sequence Time Limit: 20 Sec   Memory Limit: 64 MB Submit: 521   Solved: 159 [ Submit][ Status] Description Input Output 一个整数R Sample Input 7 9 4 8 20 14 15 18 Sample Output 13 HINT 所求的Z序列为6,7,8,13,14,15,18. R=13 左偏树+1 这题裸裸的左偏树,我却各种W…

Monkey King Time Limit: 10 Seconds      Memory Limit: 32768 KB Once in a forest, there lived N aggressive monkeys. At the beginning, they each does things in its own way and none of them knows each other. But monkeys can't avoid quarrelling, and it o…

2878: [Noi2012]迷失乐园 Time Limit: 10 Sec  Memory Limit: 512 MBSec  Special Judge Submit: 319  Solved: 223 [Submit][Status] Description 放假了,小Z认为呆在家里特别无聊,于是决定一个人去游乐园玩.进入游乐园后,小Z看了看游乐园的地图,发现能够将游乐园抽象成有n个景点.m条道路的无向连通图,且该图中至多有一个环(即m仅仅可能等于n或者n-1). 小Z如今所在的大门也正好…

Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka likes apple very much, so he has been carefully nurturing the big apple tree. The tree has N forks which are connected by branches.…

个推安卓工程师,负责公司移动端项目的架构和开发,主导移动端日志管理平台系统架构和开发工作,熟悉前后端的技术线,参与个推SDK主要业务研发工作,善于解决项目中遇到的痛点问题. 作为程序猿,每天都在写代码,但是有没有想过通过代码对写好的代码"动点手脚"呢?今天就与大家分享--如何通过用AST语法树改写Java代码. 先抛一个问题:如何将图一代码改写为图二? void someMethod(){ String rst=callAnotherMethod(); LogUtil.log(TAG,…

fork函数介绍 一个现有进程可以调用fork函数创建一个新进程.该函数定义如下: #include <unistd.h> pid_t fork(void); // 返回:若成功则在子进程中返回0,在父进程中返回子进程ID,若出错则返回-1 fork函数调用一次,返回两次.它在调用进程(称为父进程)中返回一次,返回值是新派生进程(称为子进程)的进程ID号:在子进程中返回一次,返回值为0.因此,返回值本身告知当前进程是子进程还是父进程. fork在子进程返回0而不是父进程的进程ID的原因在于:任…

BZOJ_2212_[Poi2011]Tree Rotations_线段树合并 Description Byteasar the gardener is growing a rare tree called Rotatus Informatikus. It has some interesting features: The tree consists of straight branches, bifurcations and leaves. The trunk stemming from t…

给主题的fork加一个remote 给 fork 配置一个 remote 使用 git remote -v 查看远程状态 ➜ next git:(master) git remote -v origin git@github.com:luodaoyi/hexo-theme-next.git (fetch) origin git@github.com:luodaoyi/hexo-theme-next.git (push) 把原作者的远程仓库添加到remote git remote add upst…

Apple Tree Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 22613 Accepted: 6875 Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka likes apple very much, so he has been car…

2212: [Poi2011]Tree Rotations Time Limit: 20 Sec Memory Limit: 259 MB Description Byteasar the gardener is growing a rare tree called Rotatus Informatikus. It has some interesting features: The tree consists of straight branches, bifurcations and lea…

Apple Tree Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 36442   Accepted: 10894 Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka likes apple very much, so he has bee…

20155301 滕树晨linux基础--linux进程间通信(IPC)机制总结 共享内存 共享内存是在多个进程之间共享内存区域的一种进程间的通信方式,由IPC为进程创建的一个特殊地址范围,它将出现在该进程的地址空间(这里的地址空间具体是哪个地方?)中.其他进程可以将同一段共享内存连接到自己的地址空间中.所有进程都可以访问共享内存中的地址,就好像它们是malloc分配的一样.如果一个进程向共享内存中写入了数据,所做的改动将立刻被其他进程看到 共享内存是IPC最快捷的方式,因为共享内存方式的通信没…

题目传送门 Tree Rotation 题目描述 Byteasar the gardener is growing a rare tree called Rotatus Informatikus. It has some interesting features: The tree consists of straight branches, bifurcations and leaves. The trunk stemming from the ground is also a branch.…

题目大意 一个果树(每个节点的分叉数目不固定)上有N个分叉点(包括最末的叶节点),则有N-1条边,将分叉点进行从1到N编号,每个分叉点上均可以结水果.开始的时候,每个分叉点都有一个水果,之后进行一系列操作,分为两种操作: (1)Q x: 查询分叉点x以及x的子树上的水果的总数: (2)C x: 更改分叉点x上的结果状态,即原来有水果变为没水果,没水果变为有水果     对于给定的每个Q操作,给出结果. 题目分析 典型的区间操作,但不过是单点更新,区间查询.对于区间操作,可以选用线段树或者树状数组…