题目链接 http://poj.org/problem?id=2387 题意 有n个路标,编号1~n,输入路标编号及路标之间相隔的距离,求从路标n到路标1的最短路径(由于是无向图,所以也就是求从路标1到路标n的最短路径). 思路 最短路径问题,由于结点数目最多可以有1000个,用Floyd算法应该会超时,而且做了之后发现输入会有相同的边,使用SPFA算法会麻烦一些,所以这里使用Dijkstra算法求解. 代码 #include <algorithm> #include <iostream…

题目链接:https://vjudge.net/problem/POJ-2387 题意:给n个点(<=1000),m条边(<=2000),求结点n到结点1的最短路. 思路:dijkstra优先队列,复杂度O(nlogn). AC代码: #include<cstdio> #include<queue> #include<algorithm> using namespace std; ; const int inf=0x3f3f3f3f; int m,n,cnt…

AC代码 POJ2387 Til the Cows Come Home Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to get back as quickly…

Til the Cows Come Home POJ-2387 这题是最简单的最短路求解题,主要就是使用dijkstra算法,时间复杂度是\(O(n^2)\). 需要注意的是,一定要看清楚题目的输入要求,是先输入边,再输入顶点,一开始我没看清,wrong answer了一次. package POJ; import java.util.*; public class POJ_2387 { private static int n,t; static int [][]w; static boole…

//Accepted 4688 KB 63 ms #include <cstdio> #include <cstring> #include <iostream> #include <queue> #include <cmath> #include <algorithm> using namespace std; /** * This is a documentation comment block * 如果有一天你坚持不下去了,就想…

Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to get back as quickly as possible. Farmer Joh…

Til the Cows Come Home Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 37662   Accepted: 12836 Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the…

前两天自学了一点点最短路..看起来很简单的样子... 就去kuangbin的专题找了最简单的一道题练手..然后被自己萌萌的三重for循环超时虐的不要不要的~ 松弛虽然会但是用的十分之不熟练... 代码~ #include<stdio.h> #include<string.h> #include<algorithm> using namespace std; int tance[1005][1005]; bool vis[1005]; int dis[1005]; int…

解题思路:最短路的模板题,注意一个细节处理即可. 见代码: #include<cstdio> #include<cstring> #include<algorithm> using namespace std; #define inf 0x3f3f3f3f ; int vis[maxn], w[maxn][maxn], d[maxn], t, n; void Dijkstra() { ; i <= n; i++) d[i] = w[i][n]; ; i <=…

题意梗概:据说母牛在产奶的时候,因为奶量太充足,希望有人帮它挤奶,它回家就很快.我们便能喝到鲜美的 牛奶,不过,贫奶季节却大不相同,它会懒洋洋的在大草原上晃来晃去的晒太阳,而不会想到马上回家,这可不 是好兆头,这意味着它没时间睡好觉,随之产奶的质量又会下降. 为了喝到高质量的鲜牛奶,以促进身体发育,长得更高,你希望它能尽快的回家睡觉,所以你要在给定的几条小 路中找到能回家最短的路径组合. 题目分析:还是求最短路径,可以用dijkstra算法解题,这方法我也不是特别懂,照着书上打完,再改了一下,就…