找每一位的循环节.求lcm Double Dealing Time Limit: 50000/20000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1806 Accepted Submission(s): 622 Problem Description Take a deck of n unique cards. Deal the entire deck out to…
首先将扑克牌进行一次置换,然后分解出所有的循环节,所有循环节的扑克牌个数的最小公倍数即为答案 #include <stdio.h> #include <string.h> #include <algorithm> using namespace std; #define LL long long int n,k; LL d[850],ct; int vis[850]; int a[850]; int dfs(int x) { if(!vis[a[x]]) { ct++;…
Double Dealing Time Limit: 50000/20000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1924 Accepted Submission(s): 679 Problem Description Take a deck of n unique cards. Deal the entire deck out to k players in…
# include <stdio.h> # include <algorithm> # include <string.h> using namespace std; __int64 gcd(__int64 a,__int64 b) { if(b==0) return a; return gcd(b,a%b); } int main() { int n,k,i,j,vis[810],m,num[810],x; __int64 res,cot; while(~scanf(…
Chapter 4. The class File Format Table of Contents 4.1. The ClassFile Structure 4.2. Names 4.2.1. Binary Class and Interface Names 4.2.2. Unqualified Names 4.2.3. Module and Package Names 4.3. Descriptors 4.3.1. Grammar Notation 4.3.2. Field Descript…
FatMouse' Trade Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 56784 Accepted Submission(s): 19009 Problem Description FatMouse prepared M pounds of cat food, ready to trade with the cats g…
