Java for LeetCode 135 Candy】的更多相关文章

There are N children standing in a line. Each child is assigned a rating value. You are giving candies to these children subjected to the following requirements: Each child must have at least one candy. Children with a higher rating get more candies…
135. Candy There are N children standing in a line. Each child is assigned a rating value. You are giving candies to these children subjected to the following requirements: Each child must have at least one candy. Children with a higher rating get mo…
There are N children standing in a line. Each child is assigned a rating value. You are giving candies to these children subjected to the following requirements: Each child must have at least one candy. Children with a higher rating get more candies…
原文:http://www.cnblogs.com/AndyJee/p/4483043.html There are N children standing in a line. Each child is assigned a rating value. You are giving candies to these children subjected to the following requirements: Each child must have at least one candy…
135. 分发糖果 老师想给孩子们分发糖果,有 N 个孩子站成了一条直线,老师会根据每个孩子的表现,预先给他们评分. 你需要按照以下要求,帮助老师给这些孩子分发糖果: 每个孩子至少分配到 1 个糖果. 相邻的孩子中,评分高的孩子必须获得更多的糖果. 那么这样下来,老师至少需要准备多少颗糖果呢? 示例 1: 输入: [1,0,2] 输出: 5 解释: 你可以分别给这三个孩子分发 2.1.2 颗糖果. 示例 2: 输入: [1,2,2] 输出: 4 解释: 你可以分别给这三个孩子分发 1.2.1 颗…
原题地址 遍历所有小孩的分数 1. 若小孩的分数递增,分给小孩的糖果依次+12. 若小孩的分数递减,分给小孩的糖果依次-13. 若小孩的分数相等,分给小孩的糖果设为1 当递减序列结束时,如果少分了糖果,就补上,如果多分了糖果,就减掉 究竟补多少或减多少,这很容易计算,不啰嗦了. 时间复杂度:O(n) 代码: int candy(vector<int> &ratings) { int n = ratings.size(); ; ; ; ; i < n; i++) { ]) { pr…
原题 前后两遍遍历 class Solution { public: int candy(vector<int> &ratings) { vector<int> res; int len = ratings.size(); for (int i = 0; i < len; i++) { res.push_back(1); } for (int j = 0; j < len; j++) { if (j > 0 && ratings[j] &g…
Find all possible combinations of k numbers that add up to a number n, given that only numbers from 1 to 9 can be used and each combination should be a unique set of numbers. Ensure that numbers within the set are sorted in ascending order. Example 1…
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Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same le…