转载请注明出处: http://www.cnblogs.com/fraud/          ——by fraud D. Prefixes and Suffixes You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character. Let's introduce several definitions: A substring s[i..j] (1 ≤ i ≤ j…
题目连接:Codeforces 432D Prefixes and Suffixes 题目大意:给出一个字符串,求全部既是前缀串又是后缀串的字符串出现了几次. 解题思路:依据性质能够依据KMP算法求出全部的前后缀串,然后利用dp求解,dp[i]表示从1到i这个子串出现过的次数. 转移方程dp[jump[i]]+=dp[i]. 随意一个dp[i]的初始状态应该是1. #include <cstdio> #include <cstring> const int N = 1e5+5; i…
手动转田神的大作:http://blog.csdn.net/tc_to_top/article/details/38793973 D. Prefixes and Suffixes time limit per test 1:second memory limit per test: 256 megabytes input: standard input output: standard output You have a string s = s1s2...s|s|, where |s| is…
题目链接: https://codeforces.com/contest/432/problem/D 题解: 做法一: KMP 显然next树上\(n\)的所有祖先都是答案,出现次数为next树子树大小. 做法二: 后缀数组/Z-box 按照height分组,二分查找即可. 这种题经常KMP和Z-box都能做. 另外哪位神犇教我一下扩展KMP和Z-box有啥区别. 代码 KMP: #include<cstdio> #include<cstdlib> #include<cstr…
                                                    D. Prefixes and Suffixes You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character. Let's introduce several definitions: A substring s[i..j] (1 ≤ i ≤ j ≤ |s|)…
KMP算法的综合练习 DP很久没写搞了半天才明白.本题结合Next[]的意义以及动态规划考察对KMP算法的掌握. Problem Description It is well known that AekdyCoin is good at string problems as well as number theory problems. When given a string s, we can write down all the non-empty prefixes of this str…
D. Prefixes and Suffixes time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character. Let's introduce s…
用扩展KMP做简单省力..... D. Prefixes and Suffixes time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.…
CF432D Prefixes and Suffixes 题意 给你一个长度为n的长字符串,"完美子串"既是它的前缀也是它的后缀,求"完美子串"的个数且统计这些子串的在长字符串中出现的次数 分析 求出nex数组 , 在求出每个前缀出现的次数 , 从nex[n] 往下走就行了 其实这道题是 , KMP 求每个前缀出现次数的模板题 求前缀出现次数的写法 for(int i = 1 ; i <= n ; ++i) num[i]++; for(int i = n ;…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5763 题意:给定两个字符串a和b,其中a中的字符串如果含有子串b,那么那部分可以被替换成*.问有多少种替换方法. kmp求出b在a中完全匹配后的结尾位置,然后dp(i)表示匹配到i时替换的方案数(不替换也算一次方案).首先更新dp(i)=dp(i-1),当且仅当i点是一个完全匹配的终点时,加上dp(i-nb)处的值. #include <bits/stdc++.h> using namespace…