Function overloading and return type

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Function overloading and return type

In C++ and Java, functions can not be overloaded if they differ only in the return type. For example, the following program C++ and Java programs fail in compilation. (1)C++ Program 1 #include<iostream> 2 int foo() 3 { 4 return 10; 5 } 6 7 char foo(…

error C2556: 'const char &MyString::operator [](int)' : overloaded function differs only by return type from 'char &MyString::operator [](int)'

char & operator[](int i);const char & operator[](int i);/*const char & operator(int i);*/编译出错:error C2556: 'const char &MyString::operator [](int)' : overloaded function differs only by return type from 'char &MyString::operator [](int…

[TypeScript] Infer the Return Type of a Generic Function Type Parameter

When working with conditionals types, within the “extends” expression, we can use the “infer” keyword to either get the type of the elements of an array, or even to get the return type of a function. We can use this to build a “FnReturnType” type, th…

Flask - 访问返回字典的接口报错：The view function did not return a valid response. The return type must be a string, tuple, Response instance, or WSGI callable, but it was a dict.

背景有一个 Flask 项目,然后有一个路由返回的是 dict 通过浏览器访问,结果报错关键报错信息 TypeError: 'dict' object is not callable The view function did not return a valid response. The return type must be a string, tuple, Response instance, or WSGI callable, but it was a dict. 意思是不能返回…

C++：Abstract class : invalid abstract return type for member function ‘virtual...’

#include <iostream> #include <cmath> #include <sstream> using namespace std; class aa; class bb; class root { public: virtual ~root() {} virtual root add(const aa& a) const=0; virtual root add(const bb& a) const=0; }; class aa: p…

function overloading/ declare function

Declare a function To declare a function without identifying the argument list, you can do it in this way: void say hello(...); here, you use three point (...) to indicate that the function have no argument. function overloading Keep in mind that the…

c++11: trailing return type in functions（函数返回类型后置）

In C++03, the return type of a function template cannot be generalized if the return type relies on those of the template arguments. Here is an example, mul(T a, T b) is a function template that calculates the product of a and b. Arguments a and b ar…