HDU 5514 Frogs 容斥定理】的更多相关文章

Frogs Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5514 Description There are m stones lying on a circle, and n frogs are jumping over them.The stones are numbered from 0 to m−1 and the frogs are numbered fro…
Frogs Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1315    Accepted Submission(s): 443 Problem Description There are m stones lying on a circle, and n frogs are jumping over them.The stones a…
Frogs Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1509    Accepted Submission(s): 498 Problem Description  to m−1 and the frogs are numbered from 1 to n. The i-th frog can jump over exactly …
题意:给定区间和n,求区间中与n互素的数的个数, . 思路:利用容斥定理求得先求得区间与n互素的数的个数,设表示区间中与n互素的数的个数, 那么区间中与n互素的数的个数等于.详细分析见求指定区间内与n互素的数的个数 容斥原理 AC代码 #include <cstdio> #include <cmath> #include <cctype> #include <bitset> #include <algorithm> #include <cs…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5514 题意:有m个石子围成一圈, 有n只青蛙从跳石子, 都从0号石子开始, 每只能越过xi个石子.问所有被至少踩过一次的石子的序号之和. 题解:根据裴蜀定理每个青蛙可以跳到的最小石子编号为 gcd(xi,m) = bi,所有小于 m 的 bi 的倍数都是可以到达的石头.显然所有 bi 都为 m 的因子,标记 m 中所有能到达的因子,进行容斥,比如因子2.3.6都可以到达,计算 2 和 3 的倍数的时…
GCD Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4141    Accepted Submission(s): 1441 Problem Description Given 5 integers: a, b, c, d, k, you're to find x in a...b, y in c...d that GCD(x, y)…
How many integers can you find Time Limit: 12000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3315    Accepted Submission(s): 937 Problem Description   Now you get a number N, and a M-integers set, you shoul…
Co-prime Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 935    Accepted Submission(s): 339 Problem Description Given a number N, you are asked to count the number of integers between A and B in…
GCD Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7529    Accepted Submission(s): 2773 Problem Description Given 5 integers: a, b, c, d, k, you're to find x in a...b, y in c...d that GCD(x, y…
Problem Description Given a number N, you are asked to count the number of integers between A and B inclusive which are relatively prime to N.Two integers are said to be co-prime or relatively prime if they have no common positive divisors other than…