https://leetcode.com/problems/longest-increasing-path-in-a-matrix/ Given an integer matrix, find the length of the longest increasing path. From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally o…
题目 Given an integer matrix, find the length of the longest increasing path. From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally or move outside of the boundary (i.e. wrap-around is not allowed)…
Given an integer matrix, find the length of the longest increasing path. From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally or move outside of the boundary (i.e. wrap-around is not allowed). E…
在递归调用的函数中使用了max = INT_MIN,结果报超时错误,改为max=0就对了,虽然在这题中最小就为0, 看来在之后最小为0的时候,就不要使用INT_MIN了.…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/longest-increasing-path-in-a-matrix/description/ 题目描述: Given an integer matrix, find the length of the longest increasing path. From each cell, you can either…
Given an integer matrix, find the length of the longest increasing path.From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally or move outside of the boundary (i.e. wrap-around is not allowed).Exa…
Given an integer matrix, find the length of the longest increasing path. From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally or move outside of the boundary (i.e. wrap-around is not allowed). E…
Given an integer matrix, find the length of the longest increasing path. From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally or move outside of the boundary (i.e. wrap-around is not allowed). E…
最后更新 三刷? 找矩阵里的最长路径. 看起来是DFS,实际上也就是.但是如果从每个点都进行一次DFS然后保留最大的话,会超时. 这里需要结合DP,dp[i][j]表示以此点开始的最长路径,这样每次碰到的时候,如果已经算过,可以直接调取这个值. 用空间交换了部分时间. 写的时候我吸取教训,把边界判断放在DFS的开始.. Time Complexity: 不会算.. O(4mn)?因为只能单方向= =,每个点往一个方向延伸,就不可能回来. Space : O(m*n) public class S…
688. "马"在棋盘上的概率 已知一个 NxN 的国际象棋棋盘,棋盘的行号和列号都是从 0 开始.即最左上角的格子记为 (0, 0),最右下角的记为 (N-1, N-1). 现有一个 "马"(也译作 "骑士")位于 (r, c) ,并打算进行 K 次移动. 如下图所示,国际象棋的 "马" 每一步先沿水平或垂直方向移动 2 个格子,然后向与之相垂直的方向再移动 1 个格子,共有 8 个可选的位置. 现在 "马&quo…