hdu 2425 Hiking Trip

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题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=2425 Hiking Trip Description Hiking in the mountains is seldom an easy task for most people, as it is extremely easy to get lost during the trip. Recently Green has decided to go on a hiking trip. Unfort…

hdu 2425 Hiking Trip (bfs+优先队列)

Problem Description Hiking in the mountains is seldom an easy task for most people, as it is extremely easy to get lost during the trip. Recently Green has decided to go on a hiking trip. Unfortunately, half way through the trip, he gets extremely ti…

hdu - 1242 Rescue && hdu - 2425 Hiking Trip (优先队列+bfs)

http://acm.hdu.edu.cn/showproblem.php?pid=1242 感觉题目没有表述清楚,angel的朋友应该不一定只有一个,那么正解就是a去搜索r,再用普通的bfs就能过了. 但是别人说要用优先队列来保证时间最优,我倒是没明白,步数最优跟时间最优不是等价的吗?就算士兵要花费额外时间,可是既然先到了目标点那时间不也一定是最小的? 当然用优先队列+ a去搜索r是最稳妥的. #include <cstdio> #include <cstring> #inclu…

【HDOJ】2425 Hiking Trip

优先级队列+BFS. #include <iostream> #include <cstdio> #include <cstring> #include <queue> using namespace std; #define MAXN 25 typedef struct node_st { int x, y, t; node_st() {} node_st(int xx, int yy, int tt) { x = xx; y = yy; t = tt;…

[欧拉回路] hdu 3018 Ant Trip

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=3018 Ant Trip Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1658 Accepted Submission(s): 641 Problem Description Ant Country consist of N to…

hdu 5360 Hiking(优先队列+贪心)

题目:http://acm.hdu.edu.cn/showproblem.php? pid=5360 题意:beta有n个朋友,beta要邀请他的朋友go hiking,已知每一个朋友的理想人数[L,R](现有L~R个人准备去,那么这个朋友就去). 求最多有多少人去. 及beta邀请朋友的顺序. 分析:每次邀请人的最优解就是:选会去的人里面R最小的那个人. 代码实现的话,cur代表已经准备go hiking的人数,每次将全部L<=cur的人放进优先队列,选出R最小的那个. 假设队列为空,那么剩下…