problem 1137. N-th Tribonacci Number solution: class Solution { public: int tribonacci(int n) { ) ; || n==) ; , t1 = , t2 = , t3 = ; ; i<=n; i++) { t3 = t0+t1+t2; t0 = t1; t1 = t2; t2 = t3; } return t3; } };     参考 1. Leetcode_easy_1137. N-th Tribona…

这是小川的第409次更新,第441篇原创 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第260题(顺位题号是1137).Tribonacci(泰波那契)序列Tn定义如下: 对于n> = 0,T0 = 0,T1 = 1,T2 = 1,并且T(n+3) = T(n) + T(n+1) + T(n+2). 给定n,返回Tn的值. 例如: 输入:n = 4 输出:4 说明: T_3 = 0 + 1 + 1 = 2 T_4 = 1 + 1 + 2 = 4 输入:n = 25 输出:138…

LeetCode 287. Find the Duplicate Number 暴力解法 时间 O(nlog(n)),空间O(n),按题目中Note"只用O(1)的空间",照理是过不了的,但是可能判题并没有卡空间复杂度,所以也能AC. class Solution: # 基本思路为,将第一次出现的数字 def findDuplicate(self, nums: List[int]) -> int: s = set() for i in nums: a = i in s if a…

Description e Tribonacci sequence Tn is defined as follows: T0 = 0, T1 = 1, T2 = 1, and Tn+3 = Tn + Tn+1 + Tn+2 for n >= 0. Given n, return the value of Tn. Example 1: Input: n = 4 Output: 4 Explanation: T_3 = 0 + 1 + 1 = 2 T_4 = 1 + 1 + 2 = 4 Exampl…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 动态规划 日期 题目地址:https://leetcode.com/problems/n-th-tribonacci-number/ 题目描述 The Tribonacci sequence Tn is defined as follows: T0 = 0, T1 = 1, T2 = 1, and Tn+3 = Tn + Tn+1 + Tn+2 fo…

题目如下: The Tribonacci sequence Tn is defined as follows: T0 = 0, T1 = 1, T2 = 1, and Tn+3 = Tn + Tn+1 + Tn+2for n >= 0. Given n, return the value of Tn. Example 1: Input: n = 4 Output: 4 Explanation: T_3 = 0 + 1 + 1 = 2 T_4 = 1 + 1 + 2 = 4 Example 2:…

其实思路很简单,套用一下普通斐波那契数列的非递归做法即可,不过这个成绩我一定要纪念一下,哈哈哈哈哈 代码在这儿: class Solution: def tribonacci(self, n: int) -> int: a, b, c =0, 1, 1 if n is 0: return 0 if n is 1: return 1 if n is 2: return 1 for i in range(2, n): a, b ,c = b, c, a+b+c return c…

Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify th…

题目链接 题目要求: Given a list of non negative integers, arrange them such that they form the largest number. For example, given [3, 30, 34, 5, 9], the largest formed number is 9534330. Note: The result may be very large, so you need to return a string inst…

problem 414. Third Maximum Number solution 思路:用三个变量first, second, third来分别保存第一大.第二大和第三大的数,然后遍历数组. class Solution { public: int thirdMax(vector<int>& nums) { //1.LONG_MIN; long first = LONG_MIN, second = LONG_MIN, third = LONG_MIN;// for(auto a:n…