CXF发布webservice之后访问报错: org.apache.cxf.interceptor.Fault: No binding operation info while invoking unknown method with params unknown. at org.apache.cxf.service.invoker.AbstractInvoker.invoke(AbstractInvoker.java:59) at org.apache.cxf.interceptor.Serv…

[问题]使用docker exec + sh进入容器时报错 [root@localhost home]# docker exec -it container-test bash OCI runtime exec failed: exec failed: container_linux.go:346: starting container process caused "exec: \"bash\": executable file not found in $PATH&quo…

CXF拦截器 拦截动态操作请求和响应数据 拦截器分类 位置:服务器端拦截器,客户端拦截器 消息方向:入拦截器 出拦截器 定义者:系统拦截器 自定义拦截器:LoggingInInteceptor ①:创建webservice服务端的自定义入拦截器,用于检查客户端传入的参数: package com.zhiwei.ws.imp; import java.util.List; import org.apache.cxf.binding.soap.SoapHeader; import org.apach…

在客户端生成代码之后测试出现错误: com.sun.xml.internal.ws.fault.ServerSOAPFaultException: Client received SOAP Faul 我们需要了解在客户端生成代码之后不需要引入任何的CXF的包,报上面的错误一般是调用webService接口提供的方法时, 要么就是serviceImpl没有创建成功, 或者是创建成功了,没有正确的注入. 发现webService的实现类中,忘记注入UserDao,添加之后,就正常了.也就是要正确的注…

583. Delete Operation for Two Strings Given two words word1 and word2, find the minimum number of steps required to make word1 and word2 the same, where in each step you can delete one character in either string. Example 1: Input: "sea", "e…

In the past four blogs, we attached importance to the index, including description and comparison with usage of index. Now in this blog, we will mainly focus on the basic operation of index. such query, remove ,repair and so on. 1. View Index getInde…

线段树的应用,很不错的一道题目.结点属性包括:(1)n1:1的个数:(2)c1:连续1的最大个数:(3)c0:连续0的最大个数:(4)lc1/lc0:从区间左边开始,连续1/0的最大个数:(5)rc1/rc0:从区间右边开始,连续1/0的最大个数:(6)set:置区间为0/1的标记:(7)flip:0->1, 1->0的标记.采用延迟更新.每当更新set时,flip就置为false:每当更新flip时,其实就是c1/c0, lc1/lc0, rc1/rc0的交换.对于询问最长连续1,共包括3种…

传送门 定位:思维好题. 考虑无论如何每一个W都会和前面的B在一起交换一次,所以直接求和就好了. 注意long long的使用. #include<stdio.h> #include<string.h> char s[200010]; long long ans,b; int main(){ scanf("%s",s);int n=strlen(s); for(int i=0;i<n;i++) if(s[i]=='B')b++; else ans+=b;…

模板题.S[i][j]表示i是否存在于第j个集合里.妈蛋poj差点打成poi(波兰无关)是不是没救了. #include<cstdio> #include<bitset> using namespace std; int n,m,x,y; bitset<1000>S[10001]; int main() { scanf("%d",&n); for(int i=0;i<n;++i) { scanf("%d",&…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/delete-operation-for-two-strings/description/ 题目描述 Given two words word1 and word2, find the minimum number of steps required to make word…