Design a max stack that supports push, pop, top, peekMax and popMax. push(x) -- Push element x onto stack. pop() -- Remove the element on top of the stack and return it. top() -- Get the element on the top. peekMax() -- Retrieve the maximum element i…

Design a max stack that supports push, pop, top, peekMax and popMax. push(x) -- Push element x onto stack. pop() -- Remove the element on top of the stack and return it. top() -- Get the element on the top. peekMax() -- Retrieve the maximum element i…

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…

原题链接在这里:https://leetcode.com/problems/max-stack/description/ 题目: Design a max stack that supports push, pop, top, peekMax and popMax. push(x) -- Push element x onto stack. pop() -- Remove the element on top of the stack and return it. top() -- Get th…

题意:实现栈的四个基本功能.要求:在get最小元素值时,复杂度O(1). 思路:链表直接实现.最快竟然还要61ms,醉了. class MinStack { public: MinStack(){ head.next=; head.t=; m=0x7FFFFFFF; } void push(int x) { node *p=(node *)new(node); p->t=x; p->next=head.next; head.next=p; head.t++; if(x < m) //要更…

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…

LeetCode 155:最小栈 Min Stack 设计一个支持 push,pop,top 操作,并能在常数时间内检索到最小元素的栈. push(x) -- 将元素 x 推入栈中. pop() -- 删除栈顶的元素. top() -- 获取栈顶元素. getMin() -- 检索栈中的最小元素. Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. pu…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 双栈 日期 题目地址:https://leetcode-cn.com/problems/max-stack/ 题目描述 Design a max stack that supports push, pop, top, peekMax and popMax. push(x) – Push element x onto stack. pop() – Rem…

作者:jostree 转载请注明出处 http://www.cnblogs.com/jostree/p/4052721.html 题目链接:leetcode Maximal Rectangle 单调栈 该题目是  leetcode Largest Rectangle in Histogram 的二维版本,首先进行预处理,把一个n×m的矩阵化为n个直方图,然后在每个直方图中计算使用单调栈的方法计算面积最大的矩形,然后求得最大的矩形面积即可. Ps:这题直接在网页里面敲完居然1A,不错. 代码如下:…

3.2 How would you design a stack which, in addition to push and pop, also has a function min which returns the minimum element? Push, pop and min should all operate in O(1) time. LeetCode上的原题,请参见我之前的博客Min Stack 最小栈.…