Leetcode671.Second Minimum Node In a Binary Tree二叉树中的第二小结点

【Leetcode671.Second Minimum Node In a Binary Tree二叉树中的第二小结点】的更多相关文章

Leetcode671.Second Minimum Node In a Binary Tree二叉树中的第二小结点

给定一个非空特殊的二叉树,每个节点都是正数,并且每个节点的子节点数量只能为 2 或 0.如果一个节点有两个子节点的话,那么这个节点的值不大于它的子节点的值. 给出这样的一个二叉树,你需要输出所有节点中的第二小的值.如果第二小的值不存在的话,输出 -1 . 题目应该少说了树的节点值都是大于等于0的 class Solution { public: int findSecondMinimumValue(TreeNode* root) { if(root == NULL) return -1; int…

[LeetCode] Second Minimum Node In a Binary Tree 二叉树中第二小的结点

Given a non-empty special binary tree consisting of nodes with the non-negative value, where each node in this tree has exactly two or zero sub-node. If the node has two sub-nodes, then this node's value is the smaller value among its two sub-nodes.…

LeetCode 671. Second Minimum Node In a Binary Tree二叉树中第二小的节点 (C++)

题目: Given a non-empty special binary tree consisting of nodes with the non-negative value, where each node in this tree has exactly two or zero sub-node. If the node has two sub-nodes, then this node's value is the smaller value among its two sub-nod…

[LeetCode] Closest Leaf in a Binary Tree 二叉树中最近的叶结点

Given a binary tree where every node has a unique value, and a target key k, find the value of the nearest leaf node to target k in the tree. Here, nearest to a leaf means the least number of edges travelled on the binary tree to reach any leaf of th…