Given n points in the plane that are all pairwise distinct, a "boomerang" is a tuple of points (i, j, k) such that the distance between i and j equals the distance between i and k (the order of the tuple matters). Find the number of boomerangs.…

public class Solution { /// <summary> /// 计算两个点的距离 /// </summary> /// <param name="x1"></param> /// <param name="y1"></param> /// <param name="x2"></param> /// <param name=&q…

Description Given n points in the plane that are all pairwise distinct, a "boomerang" is a tuple of points (i, j, k) such that the distance between i and j equals the distance between i and k(the order of the tuple matters). Find the number of b…

给定平面上 n 对不同的点,"回旋镖" 是由点表示的元组 (i, j, k) ,其中 i 和 j 之间的距离和 i 和 k 之间的距离相等(需要考虑元组的顺序). 找到所有回旋镖的数量.你可以假设 n 最大为 500,所有点的坐标在闭区间 [-10000, 10000] 中. 示例: 输入: [[0,0],[1,0],[2,0]] 输出: 2 解释: 两个回旋镖为 [[1,0],[0,0],[2,0]] 和 [[1,0],[2,0],[0,0]] 暴力: class Solution…