UVA 12532 Interval Product】的更多相关文章

线段树水题,忽略每个数的大小,只记住他们的正负即可,规规矩矩的代码.不过这是我第一次完全自己写的一次A的代码了.纪念一下... #include <iostream> #include <cstdio> using namespace std; #define N 100010 *N]; int x; ]; void build(int l,int r,int rt) { if(l == r) { cin>>x; ) tree[rt] = ; ) tree[rt] =…
UVA.10305 Maximum Product (暴力) 题意分析 直接枚举起点和重点,然后算出来存到数组里面,sort然后取最大值即可. 代码总览 #include <iostream> #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <sstream> #include <set> #inc…
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注意long long  long long  longlong !!!!!!   还有 printf的时候 明明longlong型的答案 用了%d  WA了也看不出,这个细节要注意!!! #include <cstdio> ]; int main() { ;long long ans,sum; while(~scanf("%d",&n)) { ;i<n;i++) scanf("%d",&a[i]); ans=; ;i<n;i…
题目链接:https://vjudge.net/contest/210334#problem/B 题目大意:Given a sequence of integers S = {S1, S2, . . . , Sn}, you should determine what is the value of the maximum positive product involving consecutive terms of S. If you cannot find a positive sequen…
[题意]:乘积最大的子序列.n∈[1,10],s∈[-10,10] [代码]: #include<bits/stdc++.h> using namespace std; int a[105]; #define LL long long int main() { int n,f=0; LL s,ma; while(~scanf("%d",&n)) { f++; ma=0; for(int i=0;i<n;i++) scanf("%d",&am…
高精度乘法问题,WA了两次是因为没有考虑结果为0的情况.  Product  The Problem The problem is to multiply two integers X, Y. (0<=X,Y<10250) The Input The input will consist of a set of pairs of lines. Each line in pair contains one multiplyer. The Output For each input pair of…
  Product of digits  For a given non-negative integer number N , find the minimal natural Q such that the product of all digits of Q is equal N . Input The first line of input contains one positive integer number, which is the number of data sets. Ea…
这道题很简单.先将N用2,3,5,7(即10以内的素数)分解因数(需要先特殊判断N不为1),然后将可以合并的因数合并(如2*2合并成4,)这样求得的结果位数会减少,大小肯定会小一些.具体实现见代码. 我的解题代码如下: #include <iostream> #include <cstdio> #include <cstring> #include <cmath> #include <cstdlib> #include <string>…
Problem D - Maximum Product Time Limit: 1 second Given a sequence of integers S = {S1, S2, ..., Sn}, you should determine what is the value of the maximum positive product involving consecutive terms ofS. If you cannot find a positive sequence, you s…