http://acm.hdu.edu.cn/showproblem.php?pid=3038 How Many Answers Are Wrong Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3648 Accepted Submission(s): 1401 Problem Description TT and FF are ... fri…

任意门:http://acm.hdu.edu.cn/showproblem.php?pid=3038 How Many Answers Are Wrong Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 15582    Accepted Submission(s): 5462 Problem Description TT and FF…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3038 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem Description TT and FF are ... friends. Uh... very very good friends -________-b FF is a bad boy, he is always…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3038 题意:就是给出n个数和依次m个问题,每个问题都是一个区间的和,然后问你这些问题中有几个有问题,有问题的直接忽略. 每个问题给出a-b之间的和为s,其实就是val(b)-val(a-1)的值为s,这样就容易想到用向量的方法来求解 #include <iostream> #include <cstring> #include <cmath> #include <cs…

传送门 Description TT and FF are ... friends. Uh... very very good friends -________-b FF is a bad boy, he is always wooing TT to play the following game with him. This is a very humdrum game. To begin with, TT should write down a sequence of integers-_…

How Many Answers Are Wrong Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2961    Accepted Submission(s): 1149 Problem Description TT and FF are ... friends. Uh... very very good friends -_____…

How Many Answers Are Wrong Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3404    Accepted Submission(s): 1310 Problem Description TT and FF are ... friends. Uh... very very good friends -_____…

Problem Description TT and FF are ... friends. Uh... very very good friends -________-bFF is a bad boy, he is always wooing TT to play the following game with him. This is a very humdrum game. To begin with, TT should write down a sequence of integer…

How Many Answers Are Wrong Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 14546    Accepted Submission(s): 5125 Problem Description TT and FF are ... friends. Uh... very very good friends -____…

题目链接 食物链类似的题,主要是在于转化,a-b的和为s,转换为b比a-1大s.然后并查集存 此节点到根的差. 假如x的根为a,y的根为b: b - y = rank[y] a - x = rank[x] y - x = s 可以推出b - a = rank[y] - rank[x] + s; 并查集 延迟更新什么的,都忘了啊. 还有这题,如果是x--的话,记得更新0的根. #include <cstring> #include <cstdio> #include <stri…