Rectangles    HDOJ(2056) http://acm.hdu.edu.cn/showproblem.php?pid=2056 题目描述:给2条线段,分别构成2个矩形,求2个矩形相交面积. 算法:先用快速排斥判断2个矩形是否相交.若不相交,面积为0.若相交,将x坐标排序去中间2个值之差,y坐标也一样.最后将2个差相乘得到最后结果. 这题是我大一的时候做过的,当时一看觉得很水,写起来发现其实没我想的那么水.分了好几类情况没做出来.今天看了点关于判断线段相交的知识,想起了这题便拿来练…

Problem Description Given two rectangles and the coordinates of two points on the diagonals of each rectangle,you have to calculate the area of the intersected part of two rectangles. its sides are parallel to OX and OY . Input Input The first line o…

Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, and all the friends do not want…

题目传送门 /* 此题为:HDOJ 1233 + HDOJ 1232 */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> using namespace std; + ; int pre[MAX_N]; int tot; int sum; struct NODE { int x, y; int len; }node[MAX_N]; int find(int…

上次因为haipz组织的比赛中有道题必须用到KMP算法,因此赛后便了解了下它,在仔细拜读了孤~影神牛的文章之后有种茅塞顿开的感觉,再次ORZ. 附上链接http://www.cnblogs.com/yjiyjige/p/3263858.html. 对于整个KMP算法,最精髓的部分便是关于next数组的生成.一开始ruijia liu的书上贴上的代码感觉完全不能理解,但是看神犇的分析觉得似乎明白了什么故写下此文来理理思路. 在整理思路之前首先记住一句话:next[j]表示的是当在str2[j]!=…

数学题,证明AB和CD.只需证明C.D在AB直线两侧,并且A.B在CD直线两侧.公式为:(ABxAC)*(ABxAD)<= 0 and(CDxCA)*(CDxCB)<= 0 #include <stdio.h> #define MAXNUM 105 typedef struct { double x1, y1; double x2, y2; } line_st; line_st lines[MAXNUM]; int cal(int i, int j) { double ab_x,…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 8693    Accepted Submission(s): 4232 Problem Description Many geometry(几何)problems were designed in the ACM/I…

Problem Description Many geometry(几何)problems were designed in the ACM/ICPC. And now, I also prepare a geometry problem for this final exam. According to the experience of many ACMers, geometry problems are always much trouble, but this problem is ve…

#include <iostream> #include <iomanip> #include <cstdlib> using namespace std; struct node { double a, b, c, d; node(){} void add(double a, double b, double c, double d){ this->a = a; this->b = b; this->c = c; this->d = d; }…

HDOJ 题目分类 //分类不是绝对的 //"*" 表示好题,需要多次回味 //"?"表示结论是正确的,但还停留在模块阶 段,需要理解,证明. //简单题看到就可以敲的 1000:    入门用: 1001:    用高斯求和公式要防溢出 1004:1012: 1013:    对9取余好了 1017:1021: 1027:    用STL中的next_permutation() 1029:1032:1037:1039:1040:1056:1064:1065: 10…