作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 栈同时保存当前值和最小值 辅助栈 同步栈 不同步栈 日期 题目地址:https://leetcode.com/problems/min-stack/description/ 题目描述 Design a stack that supports push, pop, top, and retrieving the minimum element in constan…
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…
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题目地址: https://oj.leetcode.com/problems/min-stack/ 题目内容: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() --…
写一个栈,支持push pop top getMin 难就难在在要在常量时间内返回最小的元素. 一开始乱想了很多东西,想到了HashMap,treeMap,堆什么的,都被自己一一否决了. 后来想到其实用一个栈来记录当前的最小值就好了,只有当被删除的元素等于min栈的栈顶元素时,才删除min栈里面的元素. min栈中每个元素代表着那一段栈中的最小值了. // stack: store the stack numbers private Stack<Integer> stack = new Sta…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/implement-stack-using-queues/#/description 题目描述 Implement the following operations of a stack using queues. push(x) – Push element x onto…