Chef and Mover Problem Code: CHEFMOVR Chef's dog Snuffles has so many things to play with! This time around, Snuffles has an array A containing N integers: A1, A2, ..., AN. Bad news: Snuffles only loves to play with an array in which all the elements…

Chef and Rainbow Array Problem Code: RAINBOWA Chef likes all arrays equally. But he likes some arrays more equally than others. In particular, he loves Rainbow Arrays. An array is Rainbow if it has the following structure: First a1 elements equal 1.…

Chef has an array A = (A1, A2, ..., AN), which has N integers in it initially. Chef found that for i ≥ 1, if Ai > 0, Ai+1 > 0, and Ai+2 exists, then he can decrease both Ai, andAi+1 by one and increase Ai+2 by one. If Ai+2 doesn't exist, but Ai >…

CHEFSIGN: 大厨与符号序列题目描述 大厨昨天捡到了一个奇怪的字符串 s,这是一个仅包含‘<’.‘=’和‘>’三种比较符号的字符串. 记字符串长度为 N,大厨想要在字符串的开头.结尾,和每两个字符之间插入一个正整数,共 N + 1 个数.大厨希望插入数字之后,这些比较符号所表达的含义是正确的.举个例子,如果 在‘<’前后分别插入 a 和 b,那么应当有 a < b.对于‘=’和‘>’也是类似的. 大厨可以在 [1,P] 中任意选择数字插入,同一个数也可以被插入到多个位置…

vjudge 首先显然要建立圆方树 对于每一种点建立虚树,考虑这一种点贡献,对于虚树上已经有的点就直接算 否则对虚树上的一条边 \((u, v)\),\(u\) 为父亲,假设上面连通块大小为 \(x\),下面为 \(y\) 切断 \((u, v)\) 之间的点(不包括 \(u\))都会有 \(x\times y\) 的贡献,差分一下贡献即可 # include <bits/stdc++.h> using namespace std; typedef long long ll; namespac…

Palindromic Game Problem Code: PALINGAM There are two players A, B playing a game. Player A has a string s with him, and player B has string t with him. Both s and t consist only of lower case English letters and are of equal length. A makes the firs…

Greedy Candidates Problem Code: GCAC The placements/recruitment season is going on in various colleges. The interviews are over, and each company has selected some students. But since each student can end up finally in at most one company, a student…

A String Game   Problem code: ASTRGAME   Submit All Submissions   All submissions for this problem are available. Teddy and Tracy like to play a game based on strings. The game is as follows. Initially, Tracy writes a long random string on a whiteboa…

https://www.codechef.com/DEC17/problems/CHEFEXQ 题意: 位置i的数改为k 询问区间[1,i]内有多少个前缀的异或和为k 分块 sum[i][j] 表示第i块内,有多少个前缀,他们的异或和为j a[i] 表示 位置i的数 位置i改为k: 若 g=x1^x2^x3…… 把 x1 改为 k 后,那新的g=x1^x1^k^x2^x3…… 所以修改可以看做整体异或 修改后的值^原来的值 即 区间[i,n] 异或上a[i]^k i所在块单个改,后面的块整体打标…

https://www.codechef.com/DEC17/problems/CHEFHAM #include<cstdio> #include<cstring> #include<iostream> using namespace std; #define N 100001 int a[N],b[N]; ]; int num1[N],num2[N]; void read(int &x) { x=; char c=getchar(); while(!isdig…