HDU 5916: Harmonic Value Description】的更多相关文章

Harmonic Value Description Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 0    Accepted Submission(s): 0Special Judge Problem Description The harmonic value of the permutation p1,p2,⋯pn is ∑i=1…
题目描述 The harmonic value of the permutation $p_1,p_2,\cdots p_n$ is$$\sum_{i=1}^{n-1} gcd(p_i.p_{i+1})$$Mr. Frog is wondering about the permutation whose harmonic value is the strictly k-th smallest among all the permutations of [n]. 输入 The first line…
题意:给你 n 和 m,求一个1-n的排列,使得∑gcd(Ai,Ai+1) 恰为第  m 小. 析:可以想到最小的就是相邻都互质,然后依次,第 m 小就可以有一个是gcd为 k,然后其他的为1喽. 那么我们就可以想到把 m 和2*m 拿出来,然后让其他的都相邻,那么就一定是gcd为1. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <st…
The harmonic value of the permutation p1,p2,⋯pn is ∑i=1n−1gcd(pi.pi+1) Mr. Frog is wondering about the permutation whose harmonic value is the strictly k-th smallest among all the permutations of [n]. InputThe first line contains only one integer T (…
Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 786    Accepted Submission(s): 456Special Judge Problem Description The harmonic value of the permutation p1,p2,⋯pn is ∑i=1n−1gcd(pi.pi+1) Mr. Fr…
1.2016中国大学生程序设计竞赛(长春)-重现赛 2.总结:会做的太少,应变能力也不行,或者说猜题目的能力不行 02  水 04  HDU 5914  Triangle 1.题意:1~n,n个数,问至少取出多少个数使剩下的数不构成三角形. 2.总结:比赛的时候想不出,直接数,反正n<=20..还是思维不灵活啊 3.思路:只要剩下的数都是fibnacci数列就可以. #include<iostream> #include<cstring> #include<cmath&…
目录: B - Fraction D - Triangle F - Harmonic Value Description H - Sequence I I - Sequence II B题:HDU 5912 - Fraction - [递归] 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5912 Problem DescriptionMr. Frog recently studied how to add two fractions up, an…
hdu 3652 B-number Problem Description A wqb-number, or B-number for short, is a non-negative integer whose decimal form contains the sub- string “13” and can be divided by 13. For example, 130 and 2613 are wqb-numbers, but 143 and 2639 are not. Your…
hdu 5618 Jam's problem again #include <bits/stdc++.h> #define MAXN 100010 using namespace std; int n,k,T,xx; int ans[MAXN],c[MAXN],f[MAXN]; struct Node{ int x,y,z,id; }a[100010],b[100010]; inline int read(){ char ch; bool f=false; int res=0; while (…
传送门:HDU 6787 Chess Problem Description 你现在有一个棋盘,上面有 n 个格子,格子从左往右,1,-,n 进行标号.你可以在棋盘上放置恰好 m 个传送器,并且对于每个传送器设置传送位置. 传送位置需满足:对于在 i 号格子上的传送器,传送目标位置 j 满足 j<i. 1 号格子不能放置传送器. 现在有一名玩家,拿着一枚 1,-,11 的骰子(骰子每次等概率地投出 1 到 11 中的一个数字),从位置 1开始,用骰子决定前进步数,即如果当前在位置 y 且投出数字…