Avoid The Lakes Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6826   Accepted: 3637 Description Farmer John's farm was flooded in the most recent storm, a fact only aggravated by the information that his cows are deathly afraid of wate…

题意:给出一个农田的图,n行m列,再给出k个被淹没的坐标( i , j ).求出其中相连的被淹没的农田的最大范围. 思路:dfs算法 代码: #include<iostream> #include<stdio.h> using namespace std; int t[150][150]; int visit[150][150]; int n,m,k; int dfs(int i,int j){ if(i<1||j<1||i>n||j>m||t[i][j]=…

Avoid The Lakes Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6795   Accepted: 3622 Description Farmer John's farm was flooded in the most recent storm, a fact only aggravated by the information that his cows are deathly afraid of wate…

Avoid The Lakes Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8173   Accepted: 4270 Description Farmer John's farm was flooded in the most recent storm, a fact only aggravated by the information that his cows are deathly afraid of wate…

题目 找最大的一片湖的面积,4便有1边相连算相连,4角不算. runtime error 有一种可能是 数组开的太小,越界了 #define _CRT_SECURE_NO_WARNINGS #include<stdio.h> #include<string.h> #include<math.h> #include<algorithm> #include<queue> using namespace std; #define MAXN 110 in…

Description Farmer John's farm was flooded in the most recent storm, a fact only aggravated by the information that his cows are deathly afraid of water. His insurance agency will only repay him, however, an amount depending on the size of the larges…

http://poj.org/problem?id=3620 DFS 从任意一个lake出发 重置联通的lake 并且记录 更新ans #include <iostream> #include <string.h> #include <stdio.h> using namespace std; int N,M,K; ][]; ][] = {-, , , , , , , -}; ; ; bool OK(int x, int y) { || x > N || y &l…

题目: 简单dfs,没什么好说的 代码: #include <iostream> using namespace std; typedef long long ll; #define INF 2147483647 int w,h; ][]; ][] = {-,,,,,-,,}; ; void dfs(int x,int y){ || x >= h || y < || y >= w || a[x][y] == '#') return; ans++; a[x][y] = '#';…

Lake Counting Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 18201   Accepted: 9192 Description Due to recent rains, water has pooled in various places in Farmer John's field, which is represented by a rectangle of N x M (1 <= N <= 100…

Avoid The Lakes Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 190   Accepted Submission(s) : 106 Problem Description Farmer John's farm was flooded in the most recent storm, a fact only aggrav…

Red and Black Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 12519    Accepted Submission(s): 7753 Problem Description There is a rectangular room, covered with square tiles. Each tile is color…

题意:给你N个城市和M条路和K块钱,每条路有话费,问你从1走到N的在K块钱内所能走的最短距离是多少 链接:http://poj.org/problem?id=1724 直接dfs搜一遍就是 代码: #include <stdio.h> #include <string.h> #include <iostream> #include <algorithm> #include <stdlib.h> #include <vector> #i…

题目在这里 题意 : 问你按照图中所给的提示走,多少步能走出来??? 其实只要根据这个提示走下去就行了.模拟每一步就OK,因为下一步的操作和上一步一样,所以简单dfs.如果出现loop状态,只要记忆每个所到的点的第一次的步数,最后总步数减掉它即可 /************************************************************************* > File Name: poj1573.cpp > Author: YeGuoSheng >…

1.POJ 1321  棋盘问题 2.总结: 题意:给定棋盘上放k个棋子,要求同行同列都不重. #include<iostream> #include<cstring> #include<cmath> #include<queue> #include<algorithm> #include<cstdio> #define max(a,b) a>b?a:b #define F(i,a,b) for (int i=a;i<=b…

http://poj.org/problem?id=2386 http://acm.hdu.edu.cn/showproblem.php?pid=1241 求有多少个连通子图.复杂度都是O(n*m). #include <cstdio> ][]; int n,m; void dfs(int x,int y) { ;i<=;i++) ;j<=;j++) //循环遍历8个方向 { int xx=x+i,yy=y+j; &&xx<n&&yy>=…

题目链接 题意 : 问一个m×n的矩形中,有多少个pocket,如果两块油田相连(上下左右或者对角连着也算),就算一个pocket . 思路 : 写好8个方向搜就可以了,每次找的时候可以先把那个点直接变为*,这样可以避免重复搜索. //POJ 1562 ZOJ 1709 #include <stdio.h> #include <string.h> #include <iostream> #include <stack> #include <algori…

题目链接:http://poj.org/problem?id=1321 很久没有敲搜索了啊,今天敲了个水题练练手,哈哈.... 题目大意: 就是求在n*n的方格上放置k个棋子的方案数 代码: #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> using namespace std; int n,k; ][]; ]; int sum; int ans; bool Ju…

题目:http://poj.org/problem?id=1321 最近状态有点down, 练练手 #include<cstdio> using namespace std; ][]; ],ans,n; void dfs(int x,int y) { ;i<n;i++) { if (!vis[i]&&yj[x][i]=='#') { ) { ans++; continue; } ;j<n-y+;j++) { vis[i]=; dfs(j,y-); vis[i]=;…

题意: 给你n*m的矩形,有k个坏点 问最大坏点连通块的坏点数. 一发水题.. 裸的DFS // by SiriusRen #include <cstdio> #include <algorithm> using namespace std; int n,m,k,jy,jyx,jyy,xx[]={1,-1,0,0},yy[]={0,0,1,-1},a[105][105],vis[105][105],ans=0; void dfs(int x,int y){ for(int i=0;…

转载请注明出处:https://blog.csdn.net/Mercury_Lc/article/details/82684942作者:Mercury_Lc 题目链接 题解:dfs入门,就是每个点都搜索一下,什么时候够了k个就ans++. #include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <cmath> #include <…

Apple Tree Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 27092   Accepted: 8033 Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka likes apple very much, so he has been…

http://poj.org/problem?id=3009 如果目前起点紧挨着终点,可以直接向终点滚(终点不算障碍) #include <cstdio> #include <cstring> using namespace std; ; int maz[maxn][maxn]; int n,m; ] = {,-,,}; ] = {,,,-}; bool in(int x,int y) { && x < n && y >= &&a…

POJ 1426 Find The Multiple 题意:给定一个整数n,求n的一个倍数,要求这个倍数只含0和1 参考博客:点我 解法一:普通的BFS(用G++能过但C++会超时) 从小到大搜索直至找到满足条件的数,注意最高位一定为1 假设 n=6  k即为当前所求的目标数,不满足条件则进一步递推 (i 为层数(深度),在解法二的优化中体现,此时可以不管) 1%6=1 (k=1) i=1 { (1*10+0)%6=4 (k=10) i=2 { (10*10+0)%6=4 (k=100) i=4…

POJ1979 Description There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can mo…

http://poj.org/problem?id=1564 该题运用DFS但是要注意去重,不能输出重复的答案 两种去重方式代码中有标出 第一种if(a[i]!=a[i-1])意思是如果这个数a[i]和上一个数相同,那么记录数组的同一个位置就没有必要再放入这个数.例如:4 3 3 2构成和是7,b数组的第二个位置放了3,则后面的那个3就没有必要再放入记录数组的第二个位置了.(可能会放到后面的位置)... #include<stdio.h> #include<string.h> #i…

Sum It Up Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Description Given a specified total t and a list of n integers, find all distinct sums using numbers from the list that add up to t. For example, if…

http://poj.org/problem?id=3009 模拟冰壶的移动,给出到达终点的最少投掷次数(不可达时为-1). 具体移动规则如下: 每次选四个方向之一,沿此方向一直前进,直到撞到block或出界或抵达目标位置. 如果撞到block,冰壶停在block的前一个位置,block消失,此时可改变冰壶的移动方向(重新投掷一次): 如果出界,则这条移动路径以失败结束: 如果抵达目标位置,则记录这条移动路径一共投掷的次数. 投掷次数不超过10次的为成功路径. 如果存在成功路径,输出最少的投掷次…

Curling 2.0 Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 11432   Accepted: 4831 Description On Planet MM-21, after their Olympic games this year, curling is getting popular. But the rules are somewhat different from ours. The game is…

Zhuge Liang's Mines Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 236    Accepted Submission(s): 107 Problem Description In the ancient three kingdom period, Zhuge Liang was the most famous a…

题目链接: http://poj.org/problem?id=3895 题目意思: 在无向连通图中图中找一个经过边数最多的环. 解题思路: 从任意一点直接DFS,不用回溯,注意构成环的话至少有3条边. 因为任意一个最大环,一定可以搜到. 代码: #include<iostream> #include<cmath> #include<cstdio> #include<cstdlib> #include<string> #include<cs…