How many prime numbers(求素数个数)】的更多相关文章

How many prime numbers Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 14684    Accepted Submission(s): 5091 Problem Description   Give you a lot of positive integers, just to find out how many…
385C - Bear and Prime Numbers 思路:记录数组中1-1e7中每个数出现的次数,然后用素数筛看哪些能被素数整除,并加到记录该素数的数组中,然后1-1e7求一遍前缀和. 代码: #include<bits/stdc++.h> using namespace std; #define ll long long #define pb push_back #define mem(a,b) memset((a),(b),sizeof(a)) const int INF=0x3f…
Description Some positive integers can be represented by a sum of one or more consecutive prime numbers. How many such representations does a given positive integer have? For example, the integer 53 has two representations 5 + 7 + 11 + 13 + 17 and 53…
Sum of Consecutive Prime Numbers Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 19895   Accepted: 10906 Description Some positive integers can be represented by a sum of one or more consecutive prime numbers. How many such representatio…
解题思路:给定一个数,判定它由几个连续的素数构成,输出这样的种数 用的筛法素数打表 Sum of Consecutive Prime Numbers Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 20020   Accepted: 10966 Description Some positive integers can be represented by a sum of one or more consecutive…
Prime Numbers  Descriptions: A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7. Write a program which reads a list of N integers and p…
题意:给一个数n,返回小于n的素数个数. 思路:设数字 k =from 2 to sqrt(n),那么对于每个k,从k2开始,在[2,n)范围内只要是k的倍数的都删掉(也就是说[k,k2)是不用理的,若能被筛掉早就被筛了,保留下来的就是素数).最后统计一下[2,n)内有多少个还存在的,都是素数. 要注意,如果k已经被筛掉了,那么不用再用它来删别人了,因为已经被筛掉,那么现在比k2大的且是k的倍数,都已经被干掉了. class Solution { public: int countPrimes(…
Problem Description   Give you a lot of positive integers, just to find out how many prime numbers there are.   Input   There are a lot of cases. In each case, there is an integer N representing the number of integers to find. Each integer won’t exce…
    Description: Count the number of prime numbers less than a non-negative number, n 提示晒数法: http://en.wikipedia.org/wiki/Sieve_of_Eratosthenes https://primes.utm.edu/howmany.html 别人的代码: int countPrimes(int n) { if (n<=2) return 0; vector<bool> p…
题目链接 题意:输入一个数n (2 <= n <= 10000) 有多少种方案可以把n写成若干个连续素数之和 打出10000之内的素数表,然后再打出每个可能得到的和的方案数的表 #include <iostream> #include <cstring> #include <algorithm> #include <cstdio> using namespace std; ; ],total,flag[Max + ]; ]; //可以求出1000…