题目大意: 求区间内的回文数个数 题目思路: 数位dp,先枚举前一半数字,然后填上相应的后一半数字. #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> #include<queue> #include<stack> #define MAXSIZE 1000005 #define LL long long using namespace s…

数位DP.... Palindromic Numbers Time Limit: 2000MS Memory Limit: 32768KB 64bit IO Format: %lld & %llu [Submit]   [Go Back]   [Status] Description A palindromic number or numeral palindrome is a 'symmetrical' number like 16461 that remains the same when…

A palindromic number or numeral palindrome is a 'symmetrical' number like 16461 that remains the same when its digits are reversed. In this problem you will be given two integers i j, you have to find the number of palindromic numbers between i and j…

Vinci is a little boy and is very creative. One day his teacher asked him to write all the Palindromic numbers from 1 to 1000. He became very frustrated because there is nothing creative in the task. Observing his expression, the teacher replied, "Al…

1205 - Palindromic Numbers    PDF (English) Statistics Forum Time Limit: 2 second(s) Memory Limit: 32 MB A palindromic number or numeral palindrome is a 'symmetrical' number like 16461 that remains the same when its digits are reversed. In this probl…

A palindromic number or numeral palindrome is a 'symmetrical' number like 16461 that remains the same when its digits are reversed. In this problem you will be given two integers i j, you have to find the number of palindromic numbers between i and j…

A palindromic number or numeral palindrome is a 'symmetrical' number like 16461 that remains the same when its digits are reversed. In this problem you will be given two integers i j, you have to find the number of palindromic numbers between i and j…

E - Palindromic Numbers Time Limit:2000MS     Memory Limit:32768KB     64bit IO Format:%lld & %llu Description A palindromic number or numeral palindrome is a 'symmetrical' number like 16461 that remains the same when its digits are reversed. In this…

[链接]https://cn.vjudge.net/problem/LightOJ-1205 [题意] 求出L..R范围内的回文个数 [题解] 数位DP; 先求出1..x里面的回文串个数.则做一下前缀和减掉就可以求出L..R之间的了 dfs(int start,int cur,bool ok,bool xiao){ 其中start表示是从哪一位开始进行扫描的,这个东西用来处理前导0; cur表示当前搜索到了第几位数字. ok表示当前搜索到的字符串是否为回文. xiao则表示是否出现已经搜索的某一…

题目链接:http://www.lightoj.com/volume_showproblem.php?problem=1205 题解:这题作为一个数位dp,是需要咚咚脑子想想的.这个数位dp方程可能不是很好想到,由于回文串的性质肯定要考虑到对称方面,那么不妨设dp[len][sta][flag] 表示len到sta这些字符串是否能构成回文.这里的数位dp有些特殊由于要考虑到回文的性质会涉及到回朔具体看一下代码. #include <iostream> #include <cstring&…