题面 Poj 题解 不难发现最后一位就是\(pre[n]+1\),然后消除这个位置对其他位置的贡献,从左到右扫一遍,必定有至少一个位置可以得出,循环这个过程,\(O(n^2)\)出解. #include <cmath> #include <cstdio> #include <cstring> #include <algorithm> using std::min; using std::max; using std::swap; using std::sor…
线段树 Description N (2 <= N <= 8,000) cows have unique brands in the range 1..N. In a spectacular display of poor judgment, they visited the neighborhood 'watering hole' and drank a few too many beers before dinner. When it was time to line up for the…
题意 Language:Default Lost Cows Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 13448 Accepted: 8559 Description N (2 <= N <= 8,000) cows have unique brands in the range 1..N. In a spectacular display of poor judgment, they visited the neig…
Transformation 题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=4578 Problem Description Yuanfang is puzzled with the question below: There are n integers, a1, a2, -, an. The initial values of them are 0. There are four kinds of operations. Operation 1…
从后往前查第一个为0的奶牛肯定应该排在第一个.每次从后往前找到第一个为0的数,这个数应该插在第j位.查找之后,修改节点的值为极大值,当整棵树的最小值不为0的时候查找结束. 至于这种查找修改的操作,再没有比线段树效率更高的了. #include<stdio.h> #include<string.h> #include<stdlib.h> #define N 8005 #define M 16100 struct node { int x,y; int min; int f…
Time Limit: 3000MS Memory Limit: 65536KB 64bit IO Format: %I64d & %I64u Description You have a sequence \{a_1,a_2,...,a_n\} and you can delete a contiguous subsequence of length m. So what is the minimum number of inversions after the deletion. …
