1140 Look-and-say Sequence (20 分)   Look-and-say sequence is a sequence of integers as the following: D, D1, D111, D113, D11231, D112213111, ... where D is in [0, 9] except 1. The (n+1)st number is a kind of description of the nth number. For example…

1140 Look-and-say Sequence (20 分) Look-and-say sequence is a sequence of integers as the following: D, D1, D111, D113, D11231, D112213111, ... where D is in [0, 9] except 1. The (n+1)st number is a kind of description of the nth number. For example,…

1140 Look-and-say Sequence(20 分)Look-and-say sequence is a sequence of integers as the following: D, D1, D111, D113, D11231, D112213111, ... where D is in [0, 9] except 1. The (n+1)st number is a kind of description of the nth number. For example, th…

Look-and-say sequence is a sequence of integers as the following: D, D1, D111, D113, D11231, D112213111, ... where D is in [0, 9] except 1. The (n+1)st number is a kind of description of the nth number. For example, the 2nd number means that there is…

Look-and-say sequence is a sequence of integers as the following: D, D1, D111, D113, D11231, D112213111, ... where D is in [0, 9] except 1. The (n+1)st number is a kind of description of the nth number. For example, the 2nd number means that there is…

Look-and-say sequence is a sequence of integers as the following: D, D1, D111, D113, D11231, D112213111, ... where D is in [0, 9] except 1. The (n+1)st number is a kind of description of the nth number. For example, the 2nd number means that there is…

题意:略 思路:第1个数是1(读作“1有1个”),因此第2个数就是11(读作“1有2个”),因此第3个数就是12(读作“1有1个,2有1个”),因此第4个数是1121(读作“1有2个,2有1个,1有1个”),因此第5个数是122111......懂了吧. 代码: #include <string> #include <iostream> using namespace std; int main() { int d,n; cin>>d>>n; ,d+');…

1140 Look-and-say Sequence 思路:模拟 #include<bits/stdc++.h> using namespace std; typedef long long ll; int d,n; const int maxn = 10010; int cnt[11]; vector<int> a; vector<int> b; int main(){ scanf("%d%d",&d,&n); a.push_bac…

1140 Look-and-say Sequence(20 分) 题意:观察序列D, D1, D111, D113, D11231, D112213111, ...,显然后一个串是对前一个串每一小段连续相同的字母及其个数的描述.例如,D112213111是对D11231的描述,原因是在D11231中,依次出现了1个D(即D1),2个1(即12),1个2(即21),1个3(即31),1个1(即11), 连起来即为D112213111.给定D,问符合该规律的序列中第N个数是多少? 分析: 1.C++…

oracle创建序列化: CREATE SEQUENCE seq_itv_collection            INCREMENT BY 1  -- 每次加几个              START WITH 1399       -- 从1开始计数              NOMAXVALUE        -- 不设置最大值              NOCYCLE               -- 一直累加,不循环              CACHE 10; oracle修改序列…