http://acm.hdu.edu.cn/showproblem.php?pid=5373 思路:按题意来即可. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67…

The shortest problem http://acm.hdu.edu.cn/showproblem.php?pid=5373 Time Limit: 3000/1500 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 181 Accepted Submission(s): 92 Problem Description In this problem, we should sol…

http://acm.hdu.edu.cn/showproblem.php?pid=5373 YY题,模拟下计算过程就好了,计算中并不要保存实际数(这个数会非常大),只要保存到目前为止的数字位上的和 与 奇偶位上的差即可 #pragma comment(linker, "/STACK:1677721600") #include <map> #include <set> #include <stack> #include <queue> #…

题目地址:pid=5373">HDU 5373 题意:给你一个数n和操作次数t,每次操作将n的各位数之和求出来放在n的末尾形成新的n,问t次操作后得到的n能否够被11整除. 思路:就是简单的模拟一下乱搞.额,对于%11有一个性质,当一个数的奇数位之和与偶数位之和的差的绝对值能被11整除,那么该数就能够被11整除. #include <stdio.h> #include <math.h> #include <string.h> #include <s…

题目传送门 /* 题意:题目讲的很清楚:When n=123 and t=3 then we can get 123->1236->123612->12361215.要求t次操作后,能否被11整除 同余模定理:每次操作将后缀值加到上次操作的值%11后的后面,有点绕,纸上模拟一下就行了 */ /************************************************ * Author :Running_Time * Created Time :2015-8-12 8…

The shortest problem Time Limit: 3000/1500 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 969 Accepted Submission(s): 491 Problem Description In this problem, we should solve an interesting game. At first, we have an…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5373 The shortest problem Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 995    Accepted Submission(s): 498 Problem Description In this problem, w…

The shortest problem Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 346    Accepted Submission(s): 167 Problem Description In this problem, we should solve an interesting game. At first, we hav…

The shortest problem Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 0    Accepted Submission(s): 0 Problem Description In this problem, we should solve an interesting game. At first, we have an…

题目链接:hdu_5832_A water problem 这是一个惨痛的教训,想这种这么大的大数肯定就是找个规律模拟一下. 然而我们队还写JAVA,用大数艹了13发罚时,真是TM智障了. #include<bits/stdc++.h> using namespace std; ; ; int main() { while(~scanf("%s",a)) { x=; ;a[i]!=+a[i]-; )printf("Case #%d: YES\n",ic+…