作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 动态规划 日期 题目地址:https://leetcode.com/problems/min-cost-climbing-stairs/description/ 题目描述 On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Onc…

leetcode 746. Min Cost Climbing Stairs(easy understanding dp solution) On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost…

lc 746 Min Cost Climbing Stairs 746 Min Cost Climbing Stairs On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach t…

On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step w…

题目翻译 有一个楼梯,第i阶用cost[i](非负)表示成本.现在你需要支付这些成本,可以一次走两阶也可以走一阶. 问从地面或者第一阶出发,怎么走成本最小. 测试样例 Input: cost = [10, 15, 20] Output: 15 Explanation: 从第一阶出发,一次走两步 Input: cost = [1, 100, 1, 1, 1, 100, 1, 1, 100, 1] Output: 6 Explanation: 从地面出发,走两步,走两步,走两步,走一步,走两步,走一…

题目标签:Dynamic Programming 题目给了我们一组 cost,让我们用最小的cost 走完楼梯,可以从index 0 或者 index 1 出发. 因为每次可以选择走一步,还是走两步,这里用 dynamic, 从index 2 (第三格楼梯开始) 计算每一个楼梯,到达需要用的最小cost. 在每一个楼梯,只需要计算 从前面2格楼梯过来的cost, 和 从前面1格楼梯过来的 cost,哪个小.就选哪个叠加自己的cost.最后 index = len 的地方就是走到top 所用的最小…

思路:动态规划. class Solution { //不能对cost数组进行写操作,因为JAVA中参数是引用 public int minCostClimbingStairs(int[] cost) { int cost_0 = cost[0], cost_1 = cost[1]; for(int i = 2; i < cost.length; i++) { int cost_2 = Math.min(cost_0, cost_1) + cost[i]; cost_0 = cost_1; co…

problem 746. Min Cost Climbing Stairs 题意: solution1:动态规划: 定义一个一维的dp数组,其中dp[i]表示爬到第i层的最小cost,然后来想dp[i]如何推导.思考一下如何才能到第i层呢?是不是只有两种可能性,一个是从第i-2层上直接跳上来,一个是从第i-1层上跳上来.不会再有别的方法,所以dp[i]只和前两层有关系,所以可以写做如下: dp[i] = min(dp[i- 2] + cost[i - 2], dp[i - 1] + cost[i…

On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step w…

On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step w…