Time Limit:1000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u   Description Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones. Once he thought about a string…

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A. Case of the Zeros and Ones time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing…

A. Case of the Zeros and Ones Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/556/problem/A Description Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros an…

题目传送门 /* 找规律/贪心:ans = n - 01匹配的总数,水 */ #include <cstdio> #include <iostream> #include <algorithm> #include <cstring> #include <cmath> using namespace std; ; const int INF = 0x3f3f3f3f; char s[MAXN]; int main(void) //Codeforce…

A. Case of the Zeros and Ones time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing…

A. Case of the Zeros and Ones time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing…

A. Case of the Zeros and Ones Description Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones. Once he thought about a string of length n consisting of zeroes and ones. Conside…

[Codeforces 555E]Case of Computer Network(Tarjan求边-双连通分量+树上差分) 题面 给出一个无向图,以及q条有向路径.问是否存在一种给边定向的方案,使得这q条路径都能被满足.(如果有一条边是从a->b),而经过它的路径是从b->a,那么久不满足).只需要判断,不用输出方案. 分析 对于一个有向环,显然它可以允许各个方向的路径通过.所以我们只要把无向图里的边-双联通分量建成环,然后就不用考虑了.影响答案的只有桥. 所以我们求出所有桥,然后缩点,把图…

https://codeforces.com/contest/1111/problem/D 多重排列 + 反向01背包 题意: 给你一个字符串(n<=1e5,n为偶数),有q个询问,每次询问两个位置x和y,问将和x,y相同的所有字符移到前半段或者后半段,并且剩下的所有字符都要在同一半段的方案数,字符是大写小写字母 题解: 首先不考虑x和y位置,假设前半段的排列数为\((n/2)!/(cnt[x_1]!*...*cnt[x_n]!)\),后半段的排列为\((n/2)!/(cnt[y_1]!*...…