leetcode 349 map】的更多相关文章

只需要用map来标记1,今儿通过map的值来得到重叠的部分 class Solution { public: vector<int> intersection(vector<int>& nums1, vector<int>& nums2) { map<int,int>hash; vector<int>nums3; ;i<nums1.size();i++) hash[nums1[i]]=; ;i<nums2.size()…
LeetCode 349: package com.lt.datastructure.Set; import java.util.ArrayList; import java.util.LinkedHashSet; import java.util.LinkedList; import java.util.TreeSet; /* * LeetCode409 给定两个数组,编写其中一个函数来计算他们的交集 * 说明: 输出结果中的每个元素一定是唯一的. 我们可以不考虑输出结果的顺序. 思路: 遍历…
这两道题都是求两个数组之间的重复元素,因此把它们放在一起. 原题地址: 349 Intersection of Two Arrays :https://leetcode.com/problems/intersection-of-two-arrays/description/ 350 Intersection of Two Arrays II:https://leetcode.com/problems/intersection-of-two-arrays-ii/description/ 题目&&am…
Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. Subscribe to see which companies asked…
class Solution { public: char findTheDifference(string s, string t) { map<char,int>Map_Temp; ;i<s.size();i++) Map_Temp[s[i]-'a']++; ;i<t.size();i++) Map_Temp[t[i]-'a']--; map<char,int>::iterator iter; for(iter=Map_Temp.begin();iter!=Map_…
Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. 题目标签:Hash Table 题目给了我们两个 array, 让我们找到在两…
Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [9,4] Note: Each element in the result must be unique. The…
题目: Implement a MapSum class with insert, and sum methods. For the method insert, you'll be given a pair of (string, integer). The string represents the key and the integer represents the value. If the key already existed, then the original key-value…
349. 两个数组的交集 给定两个数组,编写一个函数来计算它们的交集. 示例 1: 输入: nums1 = [1,2,2,1], nums2 = [2,2] 输出: [2] 示例 2: 输入: nums1 = [4,9,5], nums2 = [9,4,9,8,4] 输出: [9,4] 说明: 输出结果中的每个元素一定是唯一的. 我们可以不考虑输出结果的顺序. class Solution { public int[] intersection(int[] nums1, int[] nums2)…
Problem: Given two arrays, write a function to compute their intersection. 中文:已知两个数组,写一个函数来计算它们的交集 Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2],return [2, 2]. 已知nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the res…