题目 题目大意:这个题目就是大小不超过9*9的迷宫,给你起点终点和起点的方向,让你进行移动移动特别之处是不一定上下左右都可以,只有根据方向确定可以走的方向.思路:需要写一个读入函数,这个需要读入起点,终点,方向(简单),还有就是接下来几行的不同位置可以转的方向,可以写几个函数,根据函数来判断方向,最后转换成数字,用bool类型数组0,1分别代表可以或不可以.之后要写一个bfs,这个比较简单,就是和普通差不多,但是之后要输出路线,所以要有两个数组,一个用来存储路程,一个用来存储路线.具体一点的bf…

Abbott's Revenge Time limit: 3.000 seconds Abbott’s Revenge  Abbott’s Revenge The 1999 World FinalsContest included a problem based on a “dicemaze.” At the time the problem was written, the judges were unable todiscover the original source of the dic…

Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Practice UVA 816 Appoint description:   Description  Abbott’s Revenge  The 1999 World Finals Contest included a problem based on a “dice maze.” At the time the probl…

 UVA 816 -- Abbott's Revenge(BFS求最短路) 有一个 9 * 9 的交叉点的迷宫. 输入起点, 离开起点时的朝向和终点, 求最短路(多解时任意一个输出即可).进入一个交叉点的方向(用NEWS表示不同方向)不同时, 允许出去的方向也不相同. 例如:1 2 WLF NR ER * 表示如果 进去时朝W(左), 可以 左转(L)或直行(F), 如果 朝N只能右转(R) 如果朝E也只能右转.* 表示这个点的描述结束啦! 输入有: 起点的坐标, 朝向, 终点的坐标.然后是各个…

A tournament is a directed graph without self-loops in which every pair of vertexes is connected by exactly one directed edge. That is, for any two vertexes u and v (u ≠ v) exists either an edge going from u to v, or an edge from v to u. You are give…

Little Tom loves playing games. One day he downloads a little computer game called 'Bloxorz' which makes him excited. It's a game about rolling a box to a specific position on a special plane. Precisely, the plane, which is composed of several unit c…

The Robot Moving Institute is using a robot in their local store to transport different items. Of course the robot should spend only the minimum time necessary when travelling from one place in the store to another. The robot can move only along a st…

There is a rectangular grid of size n×mn×m . Each cell has a number written on it; the number on the cell (i,ji,j ) is ai,jai,j . Your task is to calculate the number of paths from the upper-left cell (1,11,1 ) to the bottom-right cell (n,mn,m ) meet…

Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around the world. Whenever a knight moves, it is two squares in one direction and one square perpendicular to this. Th…

其他题可由本题变形得到. 思路:利用坐标dfs搜索. 注意:1,初始化.2,坐标实时更新(x,y) 代码: #include<iostream> #include<cstdio> #include<cstring> #define ll long long using namespace std; ; ; char mp[amn][amn]; char ans[amn][amn]; void solve(int x,int y,int tot) { if(tot==a)…