A long-distance telephone company charges its customers by the following rules: Making a long-distance call costs a certain amount per minute, depending on the time of day when the call is made. When a customer starts connecting a long-distance call,…

A1016 Phone Bills (25)(25 分) A long-distance telephone company charges its customers by the following rules: Making a long-distance call costs a certain amount per minute, depending on the time of day when the call is made. When a customer starts con…

1016 Phone Bills (25 分)   A long-distance telephone company charges its customers by the following rules: Making a long-distance call costs a certain amount per minute, depending on the time of day when the call is made. When a customer starts connec…

题目描述 A long-distance telephone company charges its customers by the following rules: Making a long-distance call costs a certain amount per minute, depending on the time of day when the call is made. When a customer starts connecting a long-distance…

A long-distance telephone company charges its customers by the following rules: Making a long-distance call costs a certain amount per minute, depending on the time of day when the call is made. When a customer starts connecting a long-distance call,…

复建的第一题 理解题意 读懂题目就是一个活,所以我们用观察输出法,可以看出来月份,以及时间和费用之间的关系. 定义过程 然后时间要用什么来记录呢?day hour minute 好麻烦呀..用字符串吧也可以比较大小的 看到这种结果分组的(就像是数据库里面group by之后的结果)就想到用map<string,xxx> 在这道题里面,xxx就是个容器里面存放了打电话挂电话的时间戳, 这个时间戳应该是用结构体的定义,首先需要是电话或者挂电话的时间点,还有这个时间点转化为的数字,以及状态. 题意延…

题意: 输入24个正整数代表从0到23每个小时通话一分钟花费的美分.输入一个正整数N(<=1000),然后输入N组字符串,每个字符串包含客户的名字和通话的时刻以及打出或者挂断的状态. 按照字典序输出用户的名字,(每一段,按行输出)通话时长和花费,以及Total amount. trick: 对于没打通的用户(没有花费),不要输出它的Total amount.(第1,2数据点答案错误原因) AAAAAccepted code: #include<bits/stdc++.h> using n…

1016 Phone Bills (25 分) A long-distance telephone company charges its customers by the following rules: Making a long-distance call costs a certain amount per minute, depending on the time of day when the call is made. When a customer starts connecti…

06-图1 列出连通集   (25分) 给定一个有NN个顶点和EE条边的无向图,请用DFS和BFS分别列出其所有的连通集.假设顶点从0到N-1N−1编号.进行搜索时,假设我们总是从编号最小的顶点出发,按编号递增的顺序访问邻接点. 输入格式: 输入第1行给出2个整数NN(0<N\le 100<N≤10)和EE,分别是图的顶点数和边数.随后EE行,每行给出一条边的两个端点.每行中的数字之间用1空格分隔. 输出格式: 按照"{ v_1v​1​​ v_2v​2​​ ... v_kv​k​​ …

01-复杂度2 Maximum Subsequence Sum   (25分) Given a sequence of K integers { N​1​​,N​2​​, ..., N​K​​ }. A continuous subsequence is defined to be { N​i​​,N​i+1​​, ..., N​j​​ } where 1≤i≤j≤K. The Maximum Subsequence is the continuous subsequence which has…