对于每个数字二分找到大于等于它的数,再暴力找到第一个小于它的数 #include<bits/stdc++.h> #define inf 0x3f3f3f3f ; using namespace std; int b,s; int icase; ],w[maxn+]; ]; ]; bool cmp(int a,int b){ return a>b; } int firstmin(int val){ ;i<=s;i++){ if(w[i]>=val){ ; } } return…

1 match = re.search(pat,str)  If the search is successful, search() returns a match object or None otherwise. The code match = re.search(pat, str) stores the search result in a variable named "match". Then the if-statement tests the match -- if…

Problem B: CountdownTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=88443#problem/B Description Ann Sister owns a genealogical database service, which maintains family tree history for her clients. W…

this blog from: https://opendatascience.com/blog/notes-on-representation-learning-1/   Notes on Representation Learning By Zac Kriegman, Senior Data Scientist in the Thomson Reuters Data Innovation Lab | 02/07/2017 Tags: Deep Learning , Neural Networ…

Problem A 拿出勇气吧 幸运数字每一位是$4$或者$7$,现在给出一个数字每位数位上数的和为n,求出最小的幸运数n 对于100%的数据,$n\leq 10^6$ Sol : 显然本题要求数的长度尽可能短,于是显然是先放$7$放$4$并且$7$放在较低位. 这就等价于求不定方程$4x + 7y = n $的最小整数解x,然后只要延续输出x个4,y个7即可. 只需要做一次exgcd就可以求出. 复杂度应该是答案的长度 $O(length)$ # include <bits/stdc++.h>…

project 编译问题,需要三处的jdk版本要保持一致,才能编译通过. 1.在项目上右键properties->project Facets->修改右侧的version  保持一致 2.window->preferences->java->Compiler->设置右侧的Compiler compliance level 3.window->preferences->java->Installed JREs->设置或者选择右侧的Installed…

About a month ago, CodePlex have upgraded their TFS servers to to TFS 2010. While this transition was supposed to be invisible to users who connect using the SVN interface, it wasn’t. The Problem This is what I got while trying to update a project wh…

Marriage Match IV 题目链接: http://acm.hust.edu.cn/vjudge/contest/122685#problem/Q Description Do not sincere non-interference. Like that show, now starvae also take part in a show, but it take place between city A and B. Starvae is in city A and girls a…

样本类:添加了case的类便是样本类.这种修饰符可以让Scala编译器自动为这个类添加一些语法上的便捷设定. //样本类case class //层级包括一个抽象基类Expr和四个子类,每个代表一种表达式 //样本类自动添加与类名一致的工厂方法 abstract class Expr case class Var(name:String) extends Expr//括号内参数不用加val,默认为加val的字段 case class Number(num:Double) extends Expr…

We can use: ^: match the beginning $: match the end Let's say we have the string like the following: var str = `// -- // --`; What we want to do is get all the '12' which at the begining of each line: If we do like that: var regex = /^/g; To solve th…