lc 538 Convert BST to Greater Tree 538 Convert BST to Greater Tree Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original ke…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree like thi…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree like thi…

题目要求 Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. 题目分析及思路 题目给出一棵二叉搜索树,要求将它转成Greater Tree.定义Greater Tre…

problem 538. Convert BST to Greater Tree 参考 1. Leetcode_easy_538. Convert BST to Greater Tree; 完…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 日期 题目地址:https://leetcode.com/problems/convert-bst-to-greater-tree/description/ 题目描述 Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the…

题目如下: Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree li…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree like thi…

给定一个二叉搜索树(Binary Search Tree),把它转换成为累加树(Greater Tree),使得每个节点的值是原来的节点值加上所有大于它的节点值之和.例如:输入: 二叉搜索树:              5            /   \           2     13输出: 转换为累加树:             18            /   \          20     13详见:https://leetcode.com/problems/convert-…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree like thi…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree like thi…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree like thi…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree like thi…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example Given a binary search Tree ｀{5,2,3}｀: 5 / \ 2 13…

Level:   Easy 题目描述: Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary…

这是悦乐书的第255次更新,第268篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第122题(顺位题号是538).给定二进制搜索树(BST),将其转换为更大树,使原始BST的每个键都更改为原始键加上所有键的总和大于BST中的原始键.例如: 输入:二进制搜索树的根,如下所示: 5 / \ 2 13 输出:大树的根,如下所示: 18 / \ 20 13 本次解题使用的开发工具是eclipse,jdk使用的版本是1.8,环境是win7 64位系统,使用Java语言编写和测…

1.题目描述 2.问题分析 使用一个vector将所有节点的值以升序排列.然后比较,求和,加上. 3.代码 TreeNode* convertBST(TreeNode* root) { if (root == NULL) return NULL; vector<int> v; inorder(root,v); increaseVal(root, v); return root; } void increaseVal(TreeNode *root, vector<int> &…

［抄题］: 给定二叉搜索树(BST),将其转换为更大的树,使原始BST上每个节点的值都更改为在原始树中大于等于该节点值的节点值之和(包括该节点). Given a binary search Tree `{5,2,13}｀: 5 / \ 2 13 Return the root of new tree 18 / \ 20 13 [暴力解法]: 时间分析: 空间分析: ［思维问题］: ［一句话思路］: 反向求和并把和赋给root.val ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情…

https://www.cnblogs.com/grandyang/p/6591526.html 这个题本质上是中序遍历的反向.中序遍历是从小到大,而这个题目是从大到小,然后每个数加上比自己大的所有数的和. 因为实际上并没有改变树的结构,只是改变了原来树中节点的值,所以用void做返回值就可以了. 每次加sum实际上就是加的所有比当前节点大的数的和,并且这个和一定等于前一个节点的更新值. class Solution { public: TreeNode* convertBST(TreeNode…

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more th…

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never diffe…

538. 把二叉搜索树转换为累加树 给定一个二叉搜索树(Binary Search Tree),把它转换成为累加树(Greater Tree),使得每个节点的值是原来的节点值加上所有大于它的节点值之和. 例如: 输入: 原始二叉搜索树: 5 / \ 2 13 输出: 转换为累加树: 18 / \ 20 13 /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left;…

[LeetCode]99. Recover Binary Search Tree 解题报告(Python) 标签(空格分隔): LeetCode 题目地址:https://leetcode.com/problems/recover-binary-search-tree/description/ 题目描述: Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without chan…

leetcode面试准备:Implement Trie (Prefix Tree) 1 题目 Implement a trie withinsert, search, and startsWith methods. Note: You may assume that all inputs are consist of lowercase letters a-z. 2 思路 该题是实现trie树. Trie,又称单词查找树或键树,是一种树形结构.典型应用是用于统计和排序大量的字符串(但不仅限于字符…

[LeetCode]Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 递归和非递归,此提比较简单.广度优先遍历即可.关键之处就在于如何保持访问深度. 下面是4种代码: im…

原文链接:http://blog.csdn.net/jarily/article/details/8679280 /****************************************** 数据结构: BST(Binary Search Tree),二叉查找树; 性质: 若结点的左子树不空,则左子树上所有结点的值均小于它的根结点的值; 若结点的右子树不空,则右子树上所有结点的值均大于它的根结点的值; 该结点的左.右子树也分别为二叉查找树; 遍历: 对于一个已知的二叉查找树,从小到大输…

leetcode算法: Find Bottom Left Tree ValueGiven a binary tree, find the leftmost value in the last row of the tree.Example 1:Input: 2 / \ 1 3Output:1Example 2: Input: 1 / \ 2 3 / / \ 4 5 6 / 7Output:7Note: You may assume the tree (i.e., the given root n…

把二叉搜索树转换为累加树 描述 给定一个二叉搜索树(Binary Search Tree),把它转换成为累加树(Greater Tree),使得每个节点的值是原来的节点值加上所有大于它的节点值之和. 例如: 输入: 二叉搜索树: 5 / \ 2 13 输出: 转换为累加树: 18 / \ 20 13 解析 标准中序遍历,再反着遍历,每个节点的值 += 前一个节点的值. 代码 傻方法 先把树,左右全部交换,再标准中序遍历,再左右交换回来. public TreeNode convertBST(Tr…

Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 给一个二叉树,找出它的最小深度.最小深度是从根节点向下到最近的叶节点的最短路径,就是最短路径的节点个数. 解法1:DFS 解法2: BFS Java: DFS, Time Comp…

Given a binary tree, find all leaves and then remove those leaves. Then repeat the previous steps until the tree is empty. Example:Given binary tree 1 / \ 2 3 / \ 4 5 Returns [4, 5, 3], [2], [1]. Explanation: 1. Remove the leaves [4, 5, 3] from the t…