Team Queue (uva540 队列模拟)】的更多相关文章

Team Queue Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the queue in front of the Mensa is a team que…
Description   Team Queue   Team Queue  Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the queue in fron…
队列 STL队列定义在头文件<queue>中, 用“ queue<int>s ” 方式定义, 用push()和pop()进行元素的入队和出队操作, front()取队首元素(但不删除). #include<cstdio> #include<queue> #include<map> using namespace std; +; int main(){ ; &&t){ printf("Scenario #%d\n"…
题目很简单,给一个队列以及文件的位置,然后一个一个检查,如果第一个是优先级最高的就打印,否则放到队列后面,求所要打印的文件打印需要花费多长时间. 这里我用数组模拟队列实现,考虑到最糟糕的情况,必须把数组开到maxn*maxn.另外当所要打印的文件优先级不是最高的时候也需要排列到后面. 0.016s. 代码: #include <cstdio> const int maxn = 101; int t, n, m, time; int q[maxn*maxn]; int print() { int…
首发:https://mp.csdn.net/mdeditor/80294426 例题5-6 团体队列(Team Queue,UVa540) 有t个团队的人正在排一个长队.每次新来一个人时,如果他有队友在排队,那么这个 新人会插队到最后一个队友的身后.如果没有任何一个队友排队,则他会排到长队的队尾. 输入每个团队中所有队员的编号,要求支持如下3种指令(前两种指令可以穿插进 行). ENQUEUEx:编号为x的人进入长队. DEQUEUE:长队的队首出队. STOP:停止模拟. 对于每个DEQUE…
题目描述 有t个团队的人正在排一个长队.每次新来一个人时,如果他有队友在排队,那么新人会插队到最后一个队友的身后.如果没有任何一个队友排队,则他会被排到长队的队尾. 输入每个团队中所有队员的编号,要求支持如下3中指令: ENQUEUE x:编号为x的人进入长队 DEQUEUE:长队的队首出队 STOP:停止模拟 对于每个DEQUEUE指令,输出出队的人的编号 样例输入 2 3 101 102 103 3 201 202 203 ENQUEUE 101 ENQUEUE 201 ENQUEUE 10…
题目代号:UVA 540 题目链接:https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=481 题目描述: Team Queue Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2645 Ac…
Team Queue Descriptions: Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the queue in front of the Mensa…
UVA540 Team Queue 题解 题目描述:题目原题 https://vjudge.net/problem/UVA-540 Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At l…
题意: 每个人都属于一个团体,在排队的时候,如果他所在的团体有人在队伍中,则他会站到这个团体的最后.否则站到整个队伍的队尾. 输出每次出队的人的编号. 分析: 容易看出,长队中,在同一个团体的人是排在一起的. 所以用两个队列模拟即可,一个队列保留团体的编号,另外一个队列数组存放的是团体中每个人的编号. #include <cstdio> #include <queue> #include <map> using namespace std; + ; map<int…
Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the queue in front of the Mensa is a team queue, for exa…
UVA.540 Team Queue (队列) 题意分析 有t个团队正在排队,每次来一个新人的时候,他可以插入到他最后一个队友的身后,如果没有他的队友,那么他只能插入到队伍的最后.题目中包含以下操作: 1.ENQUEUE x :表示编号为x的入队: 2.DEQUEUE:长队的队首出队. 3.STOP:停止模拟 并且对于每一个DEQUEUE操作,输出队首的编号. 如果我们直接用一个队列来模拟的话,是无法实现的,原因在于,我们无法向队列中间插入元素.那么题目中还有一条重要的性质,那么就是:可以插入到…
题目原网址:http://poj.org/problem?id=2259 题目中文翻译: Description 队列和优先级队列是大多数计算机科学家已知的数据结构. 然而,Team Queue并不是很知名,尽管它常常发生在日常生活中. 例如,在午餐时间,门萨前面的队列就是Team Queue. 在Team Queue中,每个元素都属于一个团队. 如果一个元素进入队列,它首先从头到尾搜索队列,以检查它的一些队友(同一队的元素)是否已经在队列中. 如果是,它会进入Team Queue后面. 如果不…
Team Queue Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2009    Accepted Submission(s): 696 Problem Description Queues and Priority Queues are data structures which are known to most computer…
题目链接:http://poj.org/problem?id=2259 Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the queue in front o…
Team Queue Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2051    Accepted Submission(s): 713 Problem Description Queues and Priority Queues are data structures which are known to most computer…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1387 Team Queue Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1518    Accepted Submission(s): 511 Problem Description Queues and Priority Queues…
Team Queue Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1294    Accepted Submission(s): 442 Problem Description Queues and Priority Queues are data structures which are known to most computer…
Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the queue in front of the Mensa is a team queue, for exa…
Team Queue Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1889    Accepted Submission(s): 639 Problem Description Queues and Priority Queues are data structures which are known to most computer…
题目大意:托尔有一部手机可执行三种操作 1.x APP产生一个新消息 2.读取x App已产生的所有消息 3.读取前t个产生的消息 问每次操作后未读取的消息的数量 题目思路: 队列模拟,坑点在于竟然卡内存--详细看代码. #include<iostream> #include<algorithm> #include<cstring> #include<vector> #include<stdio.h> #include<stdlib.h&g…
Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the queue in front of the Mensa is a team queue, for exa…
博客地址:http://www.cnblogs.com/yudanqu/ 一.递归 递归调用:一个函数,调用的自身,称为递归调用 递归函数:一个可以调用自身的函数称为递归函数 凡是循环能干的事,递归都能干 方法: 1.写出临界条件 2.找这一次和上一次的关系 3.假设当前函数已经能用,调用自身计算上一次的结果再求出本次的结果 下面我们通过两段代码简单看一下递归和非递归的区别: 输入一个大于等于1的数,求1到n的和! # 普通函数方法 def hanshu(n): sum = 0 # 循环遍历每一…
版权声明:本文为博主原创文章.未经博主同意不得转载. https://blog.csdn.net/u013840081/article/details/26180081 题目例如以下: Team Queue  Queues and Priority Queues are data structures which are known to most computer scientists. TheTeam Queue, however, is not so well known, though…
Time Limit:3000MS     Memory Limit:0KB Description Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the q…
Team Queue Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 2977   Accepted: 1092 Description Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, thoug…
假设银行有K个窗口提供服务,窗口前设一条黄线,所有顾客按到达时间在黄线后排成一条长龙.当有窗口空闲时,下一位顾客即去该窗口处理事务.当有多个窗口可选择时,假设顾客总是选择编号最小的窗口. 有些银行会给VIP客户以各种优惠服务,例如专门开辟VIP窗口.为了最大限度地利用资源,VIP窗口的服务机制定义为:当队列中没有VIP客户时,该窗口为普通顾客服务:当该窗口空闲并且队列中有VIP客户在等待时,排在最前面的VIP客户享受该窗口的服务.同时,当轮到某VIP客户出列时,若VIP窗口非空,该客户可以选择空…
1. 前言 队列,是一种遵从先进先出(FIFO,First-In-First-Out)原则的有序集合.队列在尾部添加新元素,并从顶部移除元素,最新添加的元素必须排在队列的末尾. 2.功能说明 enqueue(value):进队,添加一个新元素到队列末尾 dequeue():出队,移除队列中的第一个元素,同时返回该元素 front():获取队列中的第一个元素 isEmpty():判断队列是否为空.是返回true,否返回fallse clear():清空队列里的元素 size():获取队列里元素的个…
主要是自己在项目中(中小型项目) 有支付下单业务(只是办理VIP,没有涉及到商品库存),目前用户量还没有上来,目前没有出现问题,但是想到如果用户量变大,下单并发量变大,可能会出现一系列的问题,趁着空闲时间,做了这个demo测试相关问题. 可能遇到的问题如下: 1.订单重复 2.高并发下,性能变慢 解决方式:ThreadPoolExecutor线程池 + Queue队列 开发工具:IDEA 15 1.首先是springBoot的项目框架如下 2.业务测试流程涉及的类,如下 BusinessThre…
python实现两个队列模拟一个栈: class Queue(object): def __init__(self): self.stack1=[] self.stack2=[] def enqueue(self, item): if len(self.stack1) == 0: self.stack1.append(item) elif len(self.stack2) == 0: self.stack2.append(item) if len(self.stack2)==1 and len(…