Charm Bracelet    POJ 3624 就是一道典型的01背包问题: #include<iostream> #include<stdio.h> #include<algorithm> #include<string.h> using namespace std; ],b[]; ]; int main() { int n,m,i,j; while(scanf("%d%d",&n,&m)!=EOF) { ;i&l…

先看个未经优化的二维空间dp: #include <iostream> #include <cstdio> #include <cmath> #include <memory.h> using namespace std; ; ; int dp[maxn2][maxn2]; //int dp[maxn2]; int w[maxn1],v[maxn2]; int m,n; int max(int x,int y) { return x>y?x:y; }…

题目链接:poj 3624 这是最基础的背包问题,特点是:每种物品仅有一件,可以选择放或不放.             用子问题定义状态:即F [i, v]表示前i件物品恰放入一个容量为v 的背包可以             获得的最大价值.则其状态转移方程便是:             F [i, v] = max{F [i − 1, v], F [i − 1, v − Ci ] + Wi }             这个方程非常重要,基本上所有跟背包相关的问题的方程都是由它衍生       …

Charm Bracelet Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 38909   Accepted: 16862 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible fro…

题目链接:http://poj.org/problem?id=3624 Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list…

POJ.3624 Charm Bracelet(DP 01背包) 题意分析 裸01背包 代码总览 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #define nmax 13000 #define nnmax 3500 using namespace std; int dp[nmax]; int w[nnmax],d[nnmax]; int main…

Charm Bracelet Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 45191   Accepted: 19318 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible fro…

Charm Bracelet Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 29295   Accepted: 13143 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible fro…

Charm Bracelet Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 34532   Accepted: 15301 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible fro…

接触动态规划的第一题是数塔问题,第二题就是01背包问题了. 当时看的懵懵懂懂,回过头来再看这道题还是非常简单的了. 用 dp[i][j] 表示取前i种物品,使它们总体积不超过j的最优取法取得的价值总和状态转移方程:dp[i][j] = max(dp[i-1][j],dp[i-1][j-cost[i]]+weight[i]) //#define LOCAL #include <iostream> #include <cstdio> #include <cstring> u…

题目链接 Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 52318   Accepted: 21912 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N(1…

Charm Bracelet Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://poj.org/problem?id=3624 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (…

题目链接:http://poj.org/problem?id=3624 思路分析: 经典的0-1背包问题: 分析如下: 代码如下: #include <iostream> using namespace std; + ; int dp[MAX_N], W[MAX_N], D[MAX_N]; int Max( int a, int b ) { return a > b ? a : b; } int main() { int n, m; memset( dp, , sizeof(dp) );…

来源:https://www.cnblogs.com/jinglecjy/p/5674796.html 题目链接:http://bailian.openjudge.cn/practice/4131/ Time Limit: 1000MS          Memory Limit: 65536K          Total Submissions: 32897          Accepted: 14587 Description Bessie has gone to the mall's…

Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weight Wi (1 ≤ Wi …

题目链接: https://vjudge.net/problem/POJ-3624 题目描述: Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N≤ 3,402) available charms. Each charm i in the sup…

DP 一直是心中痛,不多说了,这个暑假就坑在这上了. 这暑假第一道DP题,01背包问题. 题意是说物品有 重量和价值 ,但你能承受的重量有限,问你能带的最大价值. 这题数组开大点,尽管不知道有啥坑点,可是我数组开得大,直接1A了. 想想自己DP都是大问题,还要给学弟讲(tiao)题(jiao),真是忧伤. 仅仅能这几天通宵点出 DP 天赋.顺便贴上自己的理解,反正我也准备这样给学弟讲,假设有误,请路过大神指正. 论01背包的自我修养:         N个物品,M容量的包,最大价值为W.   …

Charm Bracelet Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 47876   Accepted: 20346 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible fro…

题目链接 http://poj.org/problem?id=3624 题意 有n个手镯,每个手镯有两个属性:重量W,需求因子D.还有一个背包,它能装下总重量不超过M的手镯.现在将一些镯子装入背包,求所装入镯子总需求因子的最大值. 思路 01背包问题,使用动态规划解决. 代码 #include <algorithm> #include <iostream> #include <cstring> #include <cstdio> using namespac…

  Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 3624 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms p…

题目链接:http://poj.org/problem?id=3624 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the su…

题目传送门:P2871 [USACO07DEC]手链Charm Bracelet 题目描述 Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supp…

题目描述 Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weight Wi (1 ≤ Wi ≤ 400),…

Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weight Wi (1 ≤ Wi ≤ 400), a 'd…

Charm Bracelet Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 22621   Accepted: 10157 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible fro…

A - Charm Bracelet Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%lld & %llu Submit Status Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms poss…

http://poj.org/problem?id=3624 题目大意:贝茜去了商场的珠宝店,发现了一个迷人的手镯.当然,她想装最好的魅力(N(1≤N≤3402)可用的魅力).每个魅力提供的列表中都有一个重量Wi(1≤Wi≤400),一个“愿望”因素Di(1≤Di≤100),最多可以使用一次.贝茜只能支持一个重量不超过M的魅力手镯. *第1行:两个空格分隔的整数:N和M. *第2 …N+1行:第i+1行描述了具有两个空间分离整数的魅力i: Wi和Di.考虑到重量限制作为一种约束,并列举了它们的重…

题目链接:http://poj.org/problem?id=3624 1.p[i][j]表示,背包容量为j,从i,i+1,i+2,...,n的最优解. 2.递推公式 p[i][j]=max(p[i+1][j],p[i+1][j-w[i]]+v[i]); #include <stdio.h> #include <algorithm> #include <string.h> #define NUM 3410 //物品数量的上限 #define CAP 1300 //背包容…

题目描述 Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weight Wi (1 ≤ Wi ≤ 400),…

Charm Bracelet Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weight Wi (1 ≤ …