大家好,我们今天来看一道非常非常经典的算法题--最近点对问题. 这个问题经常在各种面试当中出现,难度不低,很少有人能答上来.说实话,我也被问过,因为毫无准备,所以也没有答上来.是的,这道题有点神奇,没有准备的人往往答不上来. 题意 我们先来看下题意吧,题意很简单,在一个平面当中分布着n个点.现在我们知道这n个点的坐标,要求找出这n个点当中距离最近的两个点的间距. 我不确定这个问题是否出自于天文学,但是把它放到天文的背景当中非常合适.想象一下在浩瀚的宇宙当中,存在着无数的星辰,我们想要找到其中距离…

Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 29344    Accepted Submission(s): 7688 Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat…

大致题意:给N个点,求最近点对的距离 d :输出:r = d/2. // Time 2093 ms; Memory 1812 K #include<iostream> #include<cstdio> #include<cmath> #include<algorithm> #define eps 1e-8 #define maxn 100010 #define sqr(a) ((a)*(a)) using namespace std; int sig(dou…

Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat rings are pitched at some toys, with all the toys encircled awarded.In the field of Cyberground, the position of each toy is fixed, and the ring is carefull…

Quoit Design Time Limit: 5 Seconds      Memory Limit: 32768 KB Have you ever played quoit in a playground? Quoit is a game in which flat rings are pitched at some toys, with all the toys encircled awarded. In the field of Cyberground, the position of…

http://acm.hdu.edu.cn/showproblem.php?pid=1007 题意:平面上有n个点,问最近的两个点之间的距离的一半是多少. 思路:用分治做.把整体分为左右两个部分,那么有三种情况:最近的两个点都在左边,最近的两个点都在右边和最近的两个点一个在左边一个在右边.对于第一第二种情况,直接递归处理,分解成子问题就好了,主要是要处理第三种情况.最暴力的做法是O(n^2)的扫,这样肯定会TLE.那么要作一些优化.首先我们先递归处理得到第一种和第二种情况的答案的较小值,然后用这…

1:代码如下: // 4.4.cpp : 定义控制台应用程序的入口点. // #include "stdafx.h" #include <iostream> using namespace std; long Fac(int n) { ) ; else ); } void main() { int n ; long f; cout << "please input a number" << endl; cin >> n…

素数,不能被除了1和本身以外整除的数被称为素数.接下来我用三种方式求得1~100以内素数. 方式一 外层每循环一次,内层就计算出这个数有几个因子,我们都知道素数的因子只有两个,所以如果个数为2就加进总和里面: package day_11_25; /** * 计算1-100之间的素数和 * * @author soberw */ public class PrimeFor { public static void main(String[] args) { //记录和 int sum = 0;…

Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat rings are pitched at some toys, with all the toys encircled awarded. In the field of Cyberground, the position of each toy is fixed, and the ring is careful…

这个帖子讲得非常详细严谨,转一波. http://blog.csdn.net/lishuhuakai/article/details/9133961…