(This problem is the same as Minimize Malware Spread, with the differences bolded.) In a network of nodes, each node i is directly connected to another node j if and only if graph[i][j] = 1. Some nodes initial are initially infected by malware.  When…
In a network of nodes, each node i is directly connected to another node j if and only if graph[i][j] = 1. Some nodes initial are initially infected by malware.  Whenever two nodes are directly connected and at least one of those two nodes is infecte…
(This problem is the same as Minimize Malware Spread, with the differences bolded.) In a network of nodes, each node i is directly connected to another node j if and only if graph[i][j] = 1. Some nodes initial are initially infected by malware.  When…
题目如下: In a network of nodes, each node i is directly connected to another node j if and only if graph[i][j] = 1. Some nodes initial are initially infected by malware.  Whenever two nodes are directly connected and at least one of those two nodes is i…
In a network of nodes, each node i is directly connected to another node j if and only if graph[i][j] = 1. Some nodes initial are initially infected by malware.  Whenever two nodes are directly connected and at least one of those two nodes is infecte…
数组是算法中最常用的一种数据结构,也是面试中最常考的考点.在LeetCode题库中,标记为数组类型的习题到目前为止,已累计到了202题.然而,这202道习题并不是每道题只标记为数组一个考点,大部分习题都有两到三个考点.比如,考查数组+哈希表.数组+动态规划+数学.数组+回溯等. 看到如此多考点标签,如果盲目地按照一个标签内部所有习题的顺序去刷题,会让人有点错乱感.对于时间比较紧凑的同学来说,题目的数量比较多,想在较短时间内刷完是一个很大的挑战.因此,本文针对时间较紧凑的同学精选一些数组类型的代表…
[LeetCode]227. Basic Calculator II 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/basic-calculator-ii/description/ 题目描述: Implement a basic calculator to evaluate a simple exp…
乘风破浪:LeetCode真题_040_Combination Sum II 一.前言 这次和上次的区别是元素不能重复使用了,这也简单,每一次去掉使用过的元素即可. 二.Combination Sum II 2.1 问题 2.2 分析与解决 通过分析我们可以知道使用递归就可以解决问题,并且这次我们从头遍历一次就不会出现多次使用某一个元素了. class Solution { List<List<Integer>> ans; public List<List<Intege…
原题地址:https://oj.leetcode.com/problems/unique-binary-search-trees-ii/ 题意:接上一题,这题要求返回的是所有符合条件的二叉查找树,而上一题要求的是符合条件的二叉查找树的棵数,我们上一题提过,求个数一般思路是动态规划,而枚举的话,我们就考虑dfs了.dfs(start, end)函数返回以start,start+1,...,end为根的二叉查找树. 代码: # Definition for a binary tree node #…
1. 题目 2. 解答 2.1 方法一 在 LeetCode 206--反转链表 和 LeetCode 2--两数相加 的基础上,先对两个链表进行反转,然后求出和后再进行反转即可. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { pu…