Codeforces Round #268 (Div. 2) ABCD】的更多相关文章

CF469 Codeforces Round #268 (Div. 2) http://codeforces.com/contest/469 开学了,时间少,水题就不写题解了,不水的题也不写这么详细了. A 水题 //#pragma comment(linker, "/STACK:102400000,102400000") #include<cstdio> #include<cmath> #include<iostream> #include<…
Codeforces Round #258 (Div. 2)[ABCD] ACM 题目地址:Codeforces Round #258 (Div. 2) A - Game With Sticks 题意:  Akshat and Malvika两人玩一个游戏,横竖n,m根木棒排成#型,每次取走一个交点,交点相关的横竖两条木棒要去掉,Akshat先手,给出n,m问谁赢. 分析:  水题,非常明显无论拿掉哪个点剩下的都是(n-1,m-1),最后状态是(0,x)或(x,0),也就是拿了min(n,m)-…
Codeforces Round #354 (Div. 2) Problems     # Name     A Nicholas and Permutation standard input/output 1 s, 256 MB    x3384 B Pyramid of Glasses standard input/output 1 s, 256 MB    x1462 C Vasya and String standard input/output 1 s, 256 MB    x1393…
又掉分了0 0. A. Scarborough Fair time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Are you going to Scarborough Fair? Parsley, sage, rosemary and thyme. Remember me to one who lives there. He on…
B. Two Sets Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/468/problem/B Description Little X has n distinct integers: p1, p2, ..., pn. He wants to divide all of them into two sets A and B. The following two conditions must…
A. 24 Game Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/468/problem/A Description Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game. Initially you ha…
题目连链接:http://codeforces.com/contest/231 A. Team time limit per test:2 seconds memory limit per test:256 megabytes One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually…
比赛链接:http://codeforces.com/contest/433 A. Kitahara Haruki's Gift time limit per test:1 second memory limit per test:256 megabytes Kitahara Haruki has bought n apples for Touma Kazusa and Ogiso Setsuna. Now he wants to divide all the apples between th…
http://codeforces.com/contest/469/problem/D 题目大意: 给你一个长度为n数组,给你两个集合A.B,再给你两个数字a和b.A集合中的每一个数字x都也能在a集合中找到x-a的数字.同理,b集合也一样.问,这个数组能否分成这两个集合?(然后坑点就是集合里面的元素可以为空) 思路一: 首先定义type函数,-1表示不在任何集合内,0表示A集合内,1表示B集合,2表示该元素是a的一半.(之所以要表示成2的原因是因为这个数值很特殊,a-x=x,所以他可以满足A集合…
http://codeforces.com/contest/835 A.拼英语水平和手速的签到题 #include <bits/stdc++.h> using namespace std; int s, v1, v2, t1, t2; int main() { cin >> s >> v1 >> v2 >> t1 >> t2; int a1 = t1 + v1 * s + t1; int a2 = t2 + v2 * s + t2;…