group by DATE_FORMAT(createtime,'%Y-%m');//按月统计数据 group by DATE_FORMAT(createtime,'%Y-%m-%d');//按天统计数据 +---------------------------------+----------+ | DATE_FORMAT(createtime,'%Y-%m') | count(*) | +---------------------------------+----------+ | | |…

知识关键词:DATE_FORMAT select DATE_FORMAT(create_time,'%Y%u') weeks,count(caseid) count from tc_case group by weeks; select DATE_FORMAT(create_time,'%Y%m%d') days,count(caseid) count from tc_case group by days; select DATE_FORMAT(create_time,'%Y%m') month…

知识关键词:DATE_FORMAT select DATE_FORMAT(create_time,'%Y%u') weeks,count(caseid) count from tc_case group by weeks; select DATE_FORMAT(create_time,'%Y%m%d') days,count(caseid) count from tc_case group by days; select DATE_FORMAT(create_time,'%Y%m') month…

知识关键词:DATE_FORMAT select DATE_FORMAT(create_time,'%Y%u') weeks,count(caseid) count from tc_case group by weeks; select DATE_FORMAT(create_time,'%Y%m%d') days,count(caseid) count from tc_case group by days; select DATE_FORMAT(create_time,'%Y%m') month…

select DATE_FORMAT(create_time,'%Y%u') weeks,count(caseid) count from tc_case group by weeks; select DATE_FORMAT(create_time,'%Y%m%d') days,count(caseid) count from tc_case group by days; select DATE_FORMAT(create_time,'%Y%m') months,count(caseid) co…

select id, phone,time,year(time),month(time), DAY(time),TIME(time) from user where phone='xxxxxx' #分别取年.月.日.时间select id, phone,time from user where phone='xxxxxx' #select id, phone,time,year(time) from user where phone='xxxxxx' #分别取年select id, phone,…

select id, phone,time,year(time),month(time), DAY(time),TIME(time) from user where phone='xxxxxx'  #分别取年.月.日.时间select id, phone,time from user where phone='xxxxxx'                        #select id, phone,time,year(time) from user where phone='xxxxxx…

最近在做一个招聘网时,需要显示一个月内企业招聘信息的发布数量,按日期分组统计,刚开始是直接从源数据库表里面进行group by,但这样子就出现日期不连续的问题了,我想要的效果是,若当天没有数据,则显示为0,这样就达到连续的效果.一开始的想法是使用外连接的方法,但这样就需要另外一张日期表作为连接的对象,研究半天,也就这办法来的实在点,如下: 这里我生成从2016-1-1开始的10w条日期数据,对于连接已经够用了,下面显示的是第9w9到10w的的数据 接着,就可以用left join做连接来做日期分…

最近在工作中接到了一个需求,要求统计当月以10天为一个周期,每个周期的数据汇总信息.假设有一张表如下: 表table_test中 ID           AMOUNT         CREATE_DATE 1            50                     2017-01-01 2            50                     2017-01-09 3            50                     2017-01-11 4   …

select FROM_UNIXTIME(start_time,'%Y-%m-%d')as date,COUNT(*) FROM random_num GROUP BY FROM_UNIXTIME(start_time,'%Y-%m-%d') sql解释:在 random_num 表中将 start_time 按照 Y-m-d 的格式 进行分组,统计每天的数据条数…