状压dp Mondriaan's Dream poj2411】的更多相关文章

超经典的一道题目,实现这题的方法也有非常多种 1.利用DFS建立矩阵,然后通过高速矩阵幂得到答案(运用于min(m,n)比較小.可是max(m,n)很大的情况) 2.利用dp状压解决 第一种在我的还有一篇博客里有 http://blog.csdn.net/qwb492859377/article/details/47138821 我们在这里讨论另外一种方法. 刘汝佳的算法训练指南中384页介绍了一种复杂度O(mn*2^m)的方法,这个复杂度实在是太小了. 我对着上面敲结果仅仅用了32ms就过了这…
状压DP Mondriaan's Dream Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 9938 Accepted: 5750 Description Squares and rectangles fascinated the famous Dutch painter Piet Mondriaan. One night, after producing the drawings in his 'toilet series…
状压DP Description Squares and rectangles fascinated the famous Dutch painter Piet Mondriaan. One night, after producing the drawings in his 'toilet series' (where he had to use his toilet paper to draw on, for all of his paper was filled with squares…
Mondriaan's Dream Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 18096   Accepted: 10357 Description Squares and rectangles fascinated the famous Dutch painter Piet Mondriaan. One night, after producing the drawings in his 'toilet serie…
Mondriaan's Dream Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 17203   Accepted: 9918 Description Squares and rectangles fascinated the famous Dutch painter Piet Mondriaan. One night, after producing the drawings in his 'toilet series…
$11*11$格子板上铺$1*2$地砖方案.以前做过?权当复习算了,毕竟以前学都是浅尝辄止的..常规题,注意两个条件:上一行铺竖着的则这一行同一位一定要铺上竖的,这一行单独铺横的要求枚举集合中出现连续偶数个的1,预处理一下即可.注意数据及时reset. #include<iostream> #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include…
没错,这道题又是我从LZL里的博客里剽过来的,他的题真不错,真香. 题目链接:http://poj.org/problem?id=2411 题目大意:给一个n * m的矩形, 要求用 1 * 2的小方块去填充满这个矩形, 有多少种填充方式.(1<=n, m <= 11) 思路: 1.凭借做题的经验,能想到这道题一定是无法用暴力去解决,因为方法数肯定很多,暴力跑不出来. 2.看到这题我想到的是用状态转移,因为大的矩形填充可以由多个小的矩形填充来组成,这是最开始的想法,但是这种想法远远不够. 3.…
题目:Mondriaan's Dream 链接:http://poj.org/problem?id=2411 题意:用 1*2 的瓷砖去填 n*m 的地板,问有多少种填法. 思路: 很久很久以前便做过的一道题目,状压DP,当时写得估计挺艰辛的,今天搜插头DP又搜到它,就先用状压DP写了下,顺利多了,没一会就出来了,可惜因为long long没有1A. 思路挺简单,一行一行解决,每一列用1 表示对下一行有影响,用0 表示对下一行没有影响,所以一行最多2048 种可能,然后要筛选一下,因为有些本身就…
Mondriaan's Dream Time Limit: 3000MS Memory Limit: 65536K Description Squares and rectangles fascinated the famous Dutch painter Piet Mondriaan. One night, after producing the drawings in his 'toilet series' (where he had to use his toilet paper to d…
[题目分析] 用1*2的牌铺满n*m的格子. 刚开始用到动规想写一个n*m*2^m,写了半天才知道会有重复的情况. So Sad. 然后想到数据范围这么小,爆搜好了.于是把每一种状态对应的转移都搜了出来. 加了点优(gou)化(pi),然后poj上1244ms垫底. 大概的方法就是考虑每一层横着放的情况,剩下的必须竖起来的情况到下一层取反即可. 然后看了 <插头DP-从入门到跳楼> 这篇博客,怒抄插头DP 然后16ms了,自己慢慢YY了一下,写出了风(gou)流(pi)倜(bu)傥(tong)…