For an array A, if i < j, and A [i] > A [j], called (A [i], A [j]) is a reverse pair.return total of reverse pairs in A. ExampleGiven A = [2, 4, 1, 3, 5] , (2, 1), (4, 1), (4, 3) are reverse pairs. return 3 这道题跟LeetCode上的那道Count of Smaller Numbers A…

Given an array nums, we call (i, j) an important reverse pair if i < j and nums[i] > 2*nums[j]. You need to return the number of important reverse pairs in the given array. Example1: Input: [1,3,2,3,1] Output: 2 Example2: Input: [2,4,3,5,1] Output:…

Reverse Pairs 翻转对 题意 计算数组里面下标i小于j,但是i的值要大于j的值的两倍的搭配的个数(也就是可能会有多种搭配):网址 做法 这道题显然是不允许使用最简单的方法:两次循环,逐次进行判断,这样做的时间复杂度就是O(n^2),OJ无法通过,需要考虑另外的实现方式: class Solution(object): def reversePairs(self, nums): """ :type nums: List[int] :rtype: int "…

Reverse digits of an integer. Returns 0 when the reversed integer overflows (signed 32-bit integer). Have you met this question in a real interview?     Example Given x = 123, return 321 Given x = -123, return -321 LeetCode上的原题,请参见我之前的博客Reverse Integ…

给定一个数组 nums ,如果 i < j 且 nums[i] > 2*nums[j] 我们就将 (i, j) 称作一个重要翻转对.你需要返回给定数组中的重要翻转对的数量.示例 1:输入: [1,3,2,3,1]输出: 2示例 2:输入: [2,4,3,5,1]输出: 3注意:    给定数组的长度不会超过50000.    输入数组中的所有数字都在32位整数的表示范围内.详见:https://leetcode.com/problems/reverse-pairs/description/ C…

Given an array nums, we call (i, j) an important reverse pair if i < j and nums[i] > 2*nums[j]. You need to return the number of important reverse pairs in the given array. Example1: Input: [1,3,2,3,1] Output: 2  Example2: Input: [2,4,3,5,1] Output:…

For an array A, if i < j, and A [i] > A [j], called (A [i], A [j]) is a reverse pair.return total of reverse pairs in A.   Example Given A = [2, 4, 1, 3, 5] , (2, 1), (4, 1), (4, 3) are reverse pairs. return 3 分析: 如果用两个for loop,非常简单. public class So…

my solution: class Solution { public: int reversePairs(vector<int>& nums) { int length=nums.size(); ; ;i<length;i++) { ;j<length;j++) { if(nums[i]>2*nums[j]) count++; } } return count; } }; wrong answer : because   2147483647*2 is -2 (i…

Given an array nums, we call (i, j) an important reverse pair if i < j and nums[i] > 2*nums[j]. You need to return the number of important reverse pairs in the given array. Example1: Input: [1,3,2,3,1] Output: 2 Example2: Input: [2,4,3,5,1] Output:…

Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up:If this function…