[题目] 把N个骰子扔在地上,所有骰子朝上一面的点数之和为S.输入N,打印出S的所有可能的值出现的概率. [分析] 典型的动态规划题目. 设n个骰子的和为s出现的次数记为f(n,s),其中n=[1-N],s=[n-6n]. n=1, s=[1-6], f(n,s)=1; n=[2-N], s=[n-6n], f(n,s)= f(n-1,s-1)+ f(n-1,s-2)+ f(n-1,s-3)+ f(n-1,s-4)+ f(n-1,s-5)+ f(n-1,s-6) = sum(f(n-1,s-t)…

#-*-coding=utf-8-*- for a in range(1,50,1): for b in range(1,50,1): for c in range(1,50,1): if a+b+c==50: print a,b,c 如果是随机数咋整??: test: #-*-coding=utf-8-*- import random i=0 #计数 for a in range(1,50,1): for b in range(1,50,1): c=random.randint (1,50)…

镇场诗:---大梦谁觉,水月中建博客.百千磨难,才知世事无常.---今持佛语,技术无量愿学.愿尽所学,铸一良心博客.------------------------------------------ 1 code aCollection=range(1,101,1) print(sum(aCollection)) 2 show ------------------------------------------博文的精髓,在技术部分,更在镇场一诗.Python是优秀的语言,值得努力学习.我是跟…

http://www.practice.geeksforgeeks.org/problem-page.php?pid=387 Find sum of different corresponding bits for all pairs We define f (X, Y) as number of different corresponding bits in binary representation of X and Y. For example, f (2, 7) = 2, since b…

聪明的办法是想:求前10位,那只要前8位加起来,进2位就OK. 本的办法,就是真的加起来,截前面10位.如我. numList = str.split() sum = 0 for i in range(0,len(numList)): sum += int(numList[i][0:50]) print i,numList[i][0:50],sum print sum Work out the first ten digits of the sum of the following one-hu…

You are given a binary tree in which each node contains an integer value. Find the number of paths that sum to a given value. The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to…

B. Odd sum 题目链接:http://codeforces.com/problemset/problem/797/B time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are given sequence a1, a2, ..., an of integer numbers of length n. Your ta…

print(sum(range(101))) s = 0for i in range(101): s += iprint(s)  …

1 函数简要 map 函数  | sum 函数  |  pow函数  | lambda函数 2 简要计算 2.1 1^2 + 2^2 + 3^2 .....9^2 方法1 print([pow(x,2) for x in range(1,10)]) #[1, 4, 9, 16, 25, 36, 49, 64, 81] print(sum(pow(x,2) for x in range(1,10))) 方法2 print(map(pow,range(1,10),[2 for x in range(…

1 描述 sum() 方法对系列进行求和计算. 2 语法 sum(iterable[, start]) iterable:可迭代对象,如列表. start:指定相加的参数,如果没有设置这个值,默认为0. 3 示例 print(sum([0,1,2])) #无第二个参数,默认为0 3 print(sum([0,1,2], 10)) # 元组计算总和后再加 10 13 print(sum((0,1,2), 10)) # 列表计算总和后再加 10 13 转自http://www.runoob.com/…