[LeetCode]692. Top K Frequent Words 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/top-k-frequent-words/description/ 题目描述: Given a non-empty list of words, return the k most frequent elements. Your answer should be sorted by frequency f…
Given a non-empty list of words, return the k most frequent elements. Your answer should be sorted by frequency from highest to lowest. If two words have the same frequency, then the word with the lower alphabetical order comes first. Example 1: Inpu…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 解题方法 字典 优先级队列 日期 题目地址:https://leetcode.com/problems/top-k-frequent-elements/description/ 题目描述 Given a non-empty array of integers, return the k most frequent elements. For example,…
https://leetcode.com/problems/top-k-frequent-words/ Given a non-empty list of words, return the k most frequent elements. Your answer should be sorted by frequency from highest to lowest. If two words have the same frequency, then the word with the l…
Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: You may assume k is always valid, 1 ≤ k ≤ number of unique elements. Your algorithm's time complexity must be bet…
这个题的排序是用的PriorityQueue实现自动排列,优先队列用的是堆排序,堆排序请看:http://www.cnblogs.com/stAr-1/p/7569706.html 自定义了优先队列的排序方法,lambda表达式该复习下了... public List<String> topKFrequent(String[] words, int k) { /* 1.建立字符串和出现频率的映射 2.用优先队列PriorityQueue实现排序(相同频率用compareTo方法) 4.挑选出前…
Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k = 1 Output: [1] Note: You may assume k is always valid, 1 ≤ k ≤ number of unique ele…
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Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k = 1 Output: [1] Note: You may assume k is always valid, 1 ≤ k ≤ number of unique ele…
Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: You may assume k is always valid, 1 ≤ k ≤ number of unique elements. Your algorithm's time complexity must be bet…